C / C++ / MFC

Re: Looking for API to get the registered .txt editor

13-Dec-05 8:36

Hello,

I'm looking for an api that will give the the path to the registered .txt editor. I want my program to display a .txt file, but i don't want to make assumptions about what text editors may or may not be on the machine my code is running on.

I'm hoping i can pass ".txt" to a function, and get the default application associated with the ".txt" extension.

Thanks!

-Ian

TheGreatAndPowerfulOz13-Dec-05 9:04

Re: Looking for API to get the registered .txt editor

13-Dec-05 9:04

ShellExecute or ShellExecuteEx will automagically map the extension to the proper registered program

Ian Bowler14-Dec-05 6:54

Re: Looking for API to get the registered .txt editor

14-Dec-05 6:54

Thank you very much for taking the time to help me solve my problem. I really appreciate it!

-Ian

David Crow13-Dec-05 9:25

David Crow

13-Dec-05 9:25

What you want is either FindExecutable() or AssocQueryString().

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Re: Looking for API to get the registered .txt editor

Ian Bowler14-Dec-05 6:56

Re: Looking for API to get the registered .txt editor

14-Dec-05 6:56

Thank you very much for taking the time to help me solve my problem. FindExecutable looks like it will work for my purposes. Thanks much!

-Ian

ThatsAlok13-Dec-05 22:16

ThatsAlok

13-Dec-05 22:16

Ian Bowler wrote:
I'm hoping i can pass ".txt" to a function, and get the default application associated with the ".txt" extension.

In Continuation with Mr. Crow.. Here is Code demonstrating use of AssocQueryString :-

Using AssocQueryString to find Executable associated with the Ext.[^]

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cheers,
Alok Gupta
VC Forum Q&A :- I/ IV

Re: Looking for API to get the registered .txt editor

Ian Bowler14-Dec-05 6:56

Building and testing a deskband

14-Dec-05 6:56

Thank you very much for taking the time to help me solve my problem. I really appreciate it! I'll take a look at that example.

Thanks!

-Ian

PJ Arends13-Dec-05 8:26

PJ Arends

13-Dec-05 8:26

I need some advice, as I am obviously missing something.

I am trying to add a desk band to my project, and all seems to be going well as far as the coding part is concerned. But how do you guys handle multiple builds and testing? You know the routine, you write some code, compile and build the dll, register it and try it out, unregister the dll, repeat. But I am having problems with the repeat part. The dll stays in use by windows, so it can not be deleted and rewritten when I do a rebuild. The only way I seem to be able to do this is by rebooting the computer.

Is there some trick that I can use to force windows to unload my dll?

I am using VC6 on W2K if that makes a difference.

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TheGreatAndPowerfulOz13-Dec-05 9:07

13-Dec-05 9:07

unregister the dll
start a command shell
taskkill /f /im "explorer.exe"
start explorer.exe

PJ Arends13-Dec-05 12:48

PJ Arends

13-Dec-05 12:48

'taskkill' is not recognized...

But thanks anyway, I am able to kill explorer via task manager, and restart it via the command shell. All works great now Big Grin | :-D

TheGreatAndPowerfulOz13-Dec-05 13:10

13-Dec-05 13:10

ah taskkill is a XP command.

Address of a Class object

Aamir Butt13-Dec-05 21:07

Aamir Butt

13-Dec-05 21:07

Have u tried Process Explorer by SysInternals[^]. This will give u the exact module which is using your dll. Then you can kill that module using TaskManager.

ddmcr13-Dec-05 8:17

ddmcr

13-Dec-05 8:17

Hello guys,

I have encountered next situation and it would be nice if someone could clarify this :

class Foo
{
  public : 
	int  number1;
}Object;

int main()
{
  cout<<&Object<<endl;           // Here output is 004575E0
  cout<<&(Object.number1)<<endl; // Here output is also 004575E0
}

Does this have any eplanation Confused | :confused:

Why is the address of a class object same as its member variables address;

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C^hris L^osinger13-Dec-05 9:08

C^hris L^osinger

13-Dec-05 9:08

it makes sense if you think of a C++ object as a C-style struct.

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Dominik Reichl13-Dec-05 9:10

Dominik Reichl

13-Dec-05 9:10

Because number1 is the first member variable.

If you declare a second integer number2 below number1 in the class, its address will be 004575E4.

Best regards
Dominik

_outp(0x64, 0xAD);
and
__asm mov al, 0xAD __asm out 0x64, al
do the same... but what do they do??
(doesn't work on NT)

TheGreatAndPowerfulOz13-Dec-05 9:11

13-Dec-05 9:11

Giorgi Moniava wrote:
Why is the address of a class object same as its member variables address

Why does that confuse you? Where else do you expect the members of a class to be stored?

This is correct behavior. It is simply telling you that the first member of Foo occupies the first memory location in Foo. If you add a member after the first and take it's address, then you will see it is N1 bytes after the first member's address, where N1 is the size of the first member.

#realJSOP13-Dec-05 10:10

#realJSOP

13-Dec-05 10:10

He's obviously new at this. Give him a break.

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TheGreatAndPowerfulOz13-Dec-05 10:56