Re: CEdit control Validation - C / C++ / MFC Discussion Boards

Hachaso3-Jun-05 2:45

3-Jun-05 2:45

Thanks a lot.

The problem I get doing this is an error message when I compile.

c:\Documents and Settings\blaol\Desktop\Regional Settings Plugin\Regional Settings\Regional Settings\regionalSettingsPlugin.cpp(459): error C3861: 'EnumSystemLanguageGroups': identifier not found, even with argument-dependent lookup

Don't know what I'm doing wrong.

Re: Code example!!

sunit53-Jun-05 3:37

sunit5

3-Jun-05 3:37

Include proper header File and Library File

Re: Code example!!

eli150219793-Jun-05 5:42

eli15021979

3-Jun-05 5:42

Hi,

Based ON MSDN :
Requirements
Windows NT/2000/XP: Included in Windows 2000 and later.
Windows 95/98/Me: Unsupported.
Header: Declared in Winnls.h; include Windows.h.
Library: Use Kernel32.lib.

did you include th header files and Kernek32.Lib in your project?

Rgards,
Eli

Re: Code example!!

Hachaso6-Jun-05 23:02

Hachaso

6-Jun-05 23:02

Hi Again!

Reading a little about this callback functions I understand that
EnumSystemLanguageGroups is used with this callback function EnumLanguagesGroupsProc.

The question is how do I use them together.

EnumSystemLanguageGroups has a parameter of type, LANGUAGEGROUP_ENUMPROC. Which is passed from
EnumLanguageGroupsProc. Can you maybe give me an example of how to use them?

Thanks!

Re: Code example!!

David Crow7-Jun-05 2:53

David Crow

7-Jun-05 2:53

See here.

"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown

CEdit control Validation

laiju3-Jun-05 1:23

laiju

3-Jun-05 1:23

void EditorBasePage::DoDataExchange(CDataExchange* pDX)
{
DDV_MinMaxInt(pDX, m_nOSDItemPosX, 0, 200);
}

The above is the validation done by MFC generated code for an edit control
So any violation of data within the range(0 to 200) will be warned automatically by windows.
But windows do not highlight the edit control which was validated.
Whenever the data violation occurs,I need to set the caret selecting all the text in that particular control .
I know that SetFocus() and followed by SetSel(NULL,-1, NULL) will be do the job .But i have lot of edit boxes & I would like to know if
there are any means this will be automatically taken care by any macro.

laiju

Re: CEdit control Validation

David Crow3-Jun-05 2:30

David Crow

3-Jun-05 2:30

DDV_MinMaxInt() only validates when the OK button is clicked. I find it better to not enable the OK button until all requirements have been met. Something like:

// the OK button starts off as disabled
 
BEGIN_MESSAGE_MAP(CMyDlg, CDialog)
    //{{AFX_MSG_MAP(CMyDlg)
    ON_EN_CHANGE(IDC_EDIT1, UpdateControls)
    ON_EN_CHANGE(IDC_EDIT2, UpdateControls)
    ON_EN_CHANGE(IDC_EDIT3, UpdateControls)
    //}}AFX_MSG_MAP
END_MESSAGE_MAP()
 
void CMyDlg::UpdateControls( void ) 
{
    bool bEnable = true;
 
    // all three edit controls must be non-empty
    bEnable &= (m_edit1.GetWindowTextLength() > 0);
    bEnable &= (m_edit2.GetWindowTextLength() > 0);
    bEnable &= (m_edit3.GetWindowTextLength() > 0);
 
    // the third edit control must be within range
    CString str;
    m_edit3.GetWindowText(str);
    bEnable &= (atoi(str) >= 0 && atoi(str) <= 200);
 
    m_btnOK.EnableWindow(bEnable);
}

"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown

Re: CEdit control Validation

laiju3-Jun-05 3:57

laiju

3-Jun-05 3:57

thanx a lot for ur suggestions i shall take them

laiju

DHCP client Implementation on WindowsXP

Le Hong Anh3-Jun-05 1:08

Le Hong Anh

3-Jun-05 1:08

Dear all,

I want to write my own DHCP client.But I do not know how to start. Is this protocol could be programmed in high layer or below layer. Anyone has any idea about that or could you show me if there any sourc code of that.

RTP & RTCP implementation in C++

voipdjfzh3-Jun-05 1:02

voipdjfzh

3-Jun-05 1:02

How can i get RTP and RTCP implentation for windows

Interrogating clipboard contents

Alton Williams3-Jun-05 0:32

Alton Williams

3-Jun-05 0:32

Hi fellow developers,
I've writing a handler for WM_CHAR
What I want to do if the cut, copy or paste is used. How programatically examine what text ins in clipboard.
You help would be greatful if someone could provide me with code.
Thanks Alton

Re: Interrogating clipboard contents

Ravi Bhavnani3-Jun-05 2:03

Ravi Bhavnani

3-Jun-05 2:03

See this CP article[^] and this MSDN article[^].

/ravi

My new year's resolution: 2048 x 1536
Home | Articles | Freeware | Music
ravib@ravib.com

Re: Interrogating clipboard contents

ThatsAlok3-Jun-05 2:11

ThatsAlok

3-Jun-05 2:11

try these Api's
OpenClipboard :- for Opening Clipboard
IsClipboardFormatAvailable :- Checking the requested Data format available.

SetClipboardData/GetClipboardData :- For Geting and Setting data into or from Clipboard

"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow

cheers,
Alok Gupta

Need an Algorithm

P-Rex3-Jun-05 0:02

P-Rex

3-Jun-05 0:02

I´am working on a project where i have to query some values from a database.
I have to convert those values into letters from 'a' to 'z'.
example:
value: letter
1 -> 'a'
2 -> 'b'
3 -> 'c'
...
27 -> 'aa'
28 -> 'ab'
29 -> 'ac'

The letters can go up to 'zzzz'

Can anybody help me with this stupid thing?

P.

Re: Need an Algorithm

Cedric Moonen3-Jun-05 0:16

Cedric Moonen

3-Jun-05 0:16

Maybe something like that:

int Number = 57;        // For example
char szString[255];
strcpy(szString,"");

while (true)
{
      if (Number>=27)
      {
          strcat(szString,"a");
          Number -= 26;
      }
      else
      {
          char Temp;
          Temp = Number + 97;    // 97 is the ASCII code for 'a'
          int StrLen = strlen(szString);
          szString[StrLen] = Temp;
          szString[StrLen+1] = '\0';
          break;      //end while loop
      }
}

Ok, I didn't tested it so there could be some mistakes but this gives you the general idea

Re: Need an Algorithm

toxcct3-Jun-05 0:21

toxcct

3-Jun-05 0:21

you code won't work because you consider that if (Number>=27) only...

but if Number == 53, the result must be "ba", etc...

as P-Rex said, there are until "zzzz" possibilities, that means 26^4 = 456976 cases...

TOXCCT >>> GEII power
[toxcct][VisualCalc]

Re: Need an Algorithm

Cedric Moonen3-Jun-05 1:17

Cedric Moonen

3-Jun-05 1:17

I think you didn't understand completely my code Wink | ;)

For exemple if Number == 53, the result must be "ab" and not "ba".
Thus in my code, if (Number >= 27), I DON'T jump out of the loop but comes once again in the loop, thus adding 'b' to the already existing string (that contains 'a').

Is it a little bit clearer ?

[EDIT] Sorry, I don't add 'b' but 'z' because 53-27 = 26 that corresponds to 'z' Smile | :)

[EDIT2] After 2 minutes of reflexion, I see that there effectively a problem in the code Unsure | :~

. There will only be 'a' in the begining of the string... I must not subtract but rather divide by 26... But I think the other solutions are good

Re: Need an Algorithm

camoguard3-Jun-05 4:05

camoguard

3-Jun-05 4:05

You sound like you have it. But in case you haven't thought of this, you can imagine you are working with a base 27 system of numbers and you are converting from decimal.

Begin by checking if your value is greater than (27^3+1) if it is get the mod of your input number by (27^3+1 because a is 1), that's your first digit which falls between 0 and 26. then subtract that number off your working total. Then check if the remainder is bigger than (27^2+1). If it is, then mod by (27^2+1), that's your second digit. And so on. Since you are working with a-z just add the value of the char('a') to each mod and save yourself a switch statement. One for loop of four iterations should do it.

Re: Need an Algorithm

Andrew Kirillov3-Jun-05 0:29

Andrew Kirillov

3-Jun-05 0:29

<br />
	CString	str;<br />
	int number = 53;<br />
<br />
	do<br />
	{<br />
		number--;<br />
		str.Insert(0, 'a' + (number % 26));<br />
		number /= 26;<br />
	}<br />
	while (number > 0);<br />
<br />
	TRACE(_T("str: %s"), str);<br />

Re: Need an Algorithm

P-Rex3-Jun-05 1:23

P-Rex

3-Jun-05 1:23

Thanks, you are my hero.
I didn´t thought that this is so easy Big Grin | :-D

Pascal

Re: Need an Algorithm

Tim Smith3-Jun-05 3:43

Tim Smith

3-Jun-05 3:43

As he properly realized, going from a number to a 'A' to 'ZZZZ' representation is the same as printing the number base 26 where the digits are the letters 'A' - 'Z'. If you wanted to write a number converter to print that value as decimal, then just change the / 26 to / 10 and the initial character from 'A' to '0'.

Tim Smith

I'm going to patent thought. I have yet to see any prior art.

Re: Need an Algorithm

toxcct3-Jun-05 0:33

toxcct

3-Jun-05 0:33

<font color=blue>int</font> iVal = 453; <font color=green>// For example</font>
<font color=blue>char</font> Result[5] = <font color=gray>""</font>;
 
<font color=blue>if</font> (iVal >= 17577) {  <font color=green>// For the most left character</font>
    Result[0] = (iVal % 26) - 1 + <font color=gray>'A'</font>;
}
<font color=blue>else</font> {
    Result[0] = <font color=gray>'\0'</font>;
}
 
<font color=blue>if</font> (iVal >= 677) {  <font color=green>// For the second left character</font>
    Result[1] = (iVal % 26) - 1 + <font color=gray>'A'</font>;
}
<font color=blue>else</font> {
    Result[1] = <font color=gray>'\0'</font>;
}
 
<font color=blue>if</font> (iVal >= 27) {  <font color=green>// For the third left character</font>
    Result[2] = (iVal % 26) - 1 + <font color=gray>'A'</font>;
}
<font color=blue>else</font> {
    Result[2] = <font color=gray>'\0'</font>;
}

<font color=blue>if</font> (iVal >= 1) {  <font color=green>// For the most right character</font>
    Result[3] = (iVal % 26) - 1 + <font color=gray>'A'</font>;
}
<font color=blue>else</font> {
    Result[3] = <font color=gray>'\0'</font>;
}
 
Result[4] = <font color=gray>'\0'</font>;
 
<font color=green>// Re-order the string (erases the '\0' at the beginning of the string)...</font>
<font color=blue>for</font> (int</font> i = 0, i < 4, i++) {
    <font color=blue>if</font> (Result[1] == <font color=gray>'\0'</font>) {
        Result[i] = Result[i+1];
    }
}