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hi,
<xs:any> should do the job.
W3C XML Schema spec.[^]
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
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When I change it I get this exception "The 'http://www.w3.org/2001/XMLSchema:any' element is not supported in this context". Any advice.
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Nevermind, I changed it to
<xs:complexType name="Node4">
<xs:sequence>
<xs:any namespace="##any" minOccurs="0" maxOccurs="unbounded" processContents="skip" />
<xs:sequence>
<xs:complexType>
<xs:element name="Node4" type="Node4" minOccurs="0" maxOccurs="1" />
Maybe not that exactly, but it worked. Thanks for the help
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I have been teaching myself XML for a short time noe, and I want to move into using it with JavaScript for web sites. However, I would like to avoid using the typical "new ActiveXObject(Microsoft.XMLDOM)" line. Is there an alternative to ActiveX/Microsoft?
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 :->:->:->
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I'm new to XML and today a guy asked me how to get to a particular node in a very big XML file(1-2 Gigs).
Do you guys have any ideas?
Thanks so much.
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Anonymous wrote:
very big XML file(1-2 Gigs)
 That's not good...
Well first (obvious) idea is not to read whole XML document to memory - XmlDocumentXmlTextReader, bt I am not sure how to get particular node - is it described with XPath or ...how?
Anonymous wrote:
I'm new to XML
hmm in case you don't know XPath, XmlDocument, XmlTextReader etc. feel free to ask - or google 
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
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Hi, i want to display info from 2 tables [users] and [friends]. there are a relations between users.id and friends.iduser. when i display i only can display the info from the table [users].
Anyone could help me on displaying info from relations tables? any has a little example plz?
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hmmm, that looks like SQL problem... how does it go with XML/XSL?
Anyway, if it is SQL, you can do something like
SELECT users.name, friends.idontknowhat FROM users, friends WHERE users.id = friends.iduser
or is it in XML? 
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
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i have declared two XML objects the first has as datasrc=select * from users and the 2 has select * from users where iduser=@iduser, the problem that i have is that i dont know how to pass the second variable , the iduser from the first xml object, is this posible??
any sugerencies?
thanks
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Can anyone give me a detailed explaination about when to use CSS and XSLFO?
What are the advantages between them. Which is more efficient interms of
maintence.
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My question is can we serialize an array (array of objects) at a time in .Net. Can anybody annswer me........
Thanx
Pradosh
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Did you try? 
As quick look at MSDN shows it (System.Array) has [Serializable] attribute, so I guess answer is YES.
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
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Here's my code:
try
{
_strContent = "<Employees><Employee id=\"1\"><Name>Ethan</Name></Employee></Employees>"
_xmlDoc.Load(".\\EMP.xml");
_docFrag = _xmlDoc.CreateDocumentFragment();
_docFrag.InnerXml = _strContent;
_xmlDoc.DocumentElement.AppendChild(_docFrag);
_xmlDoc.Save(".\\EMP.xml");
}
catch(Exception exc)
{
MessageBox.Show(exc.ToString());
}
The EMP.xml is already existing. I just used the above block of code to add new nodes into an existing EMP.xml file. But, I received this exception:
This is an unexpected token. The expected token is 'EndElement'
Unlikely though, the code performs its function. When I check the file, I saw that the node I am trying to add was there, its just that the error keeps on prompting. Will anyone help me? Thanks in advance!
----------------------
Seeing the infinite...
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well I don't know what exactly is problem there, maybe you already solved it (?).
Ethan Marixxe Drater wrote:
This is an unexpected token. The expected token is 'EndEleme
That means syntax error in your XML. Surprisingly.
Ethan Marixxe Drater wrote:
Unlikely though, the code performs its function. When I check the file, I saw that the node I am trying to add was there, its just that the error keeps on prompting.
Strange.
Could you post small examples of input/output? Or at least where exactly exception raises? I mean what statement? _xmlDoc.Load(), _xmlDoc.Save(), AppendChild?
Funny how can be debugging something about 10 lines difficult. I just failed test cuz of the same
David
Never forget: "Stay kul and happy" (I.A.)
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Hi David!I was able to fix it. I simply forget to close the node Thanks for the help.
----------------------
Seeing the infinite...
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How could i convert XML file to STRING?
Here's my sample file...
Books.xml
<Books>
<Book>
<Title>Angels and Demons</Title>
<Author>Dan Brown</Author>
</Book>
</Books>
----------------------
Seeing the infinite...
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hmmm. Could you delete your next "posts"? I mean you should MODIFY this one, not to post it again. If you didn't notice, there is magical "modify" link that allows you to edit your post. "delete" is right next to it Thank you.
As for your question... How do you want output to look like? If you have XML file and you want to have string with ALL markup, simple solution is to load it with System.IO.TextReader.
If you want to get only "Dan Brown", you should use classes from System.XmlNamespace. You can use XmlTextReader (similar way as TextReader, bt it reads XML nodes not characters or lines like TextReader) or XmlDocument (easy - it has Load(filename) method). To get "Dan Brown" text, you have to read <Author> element - with XmlTextReader use
this link cuz I just realized that I have lot of work now... sorry[^]
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
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Hi David, thanks for your help, I think i'll prefer the use of TextReader.
----------------------
Seeing the infinite...
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I am not a C# person nor am I a XML person.
But I have enough skills I can fake it. Could you suggest a C# book that has a basic
1. Read an XML file
2. Determine that it is well formated.
3. Validate the scheme.
4. Write the result.
thanks
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Your first visit should be www.w3c.org for items 2 and 3,
for 1 and 4 ado.net
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hello ,
I have a problem in retreiving the innerXml values from an XML File . The File is pasted below and the method I use is also listed below .
I want to list out the values Sylesh1,Sylesh2,sylesh3........ sylesh9 to an
arrayList .
The Method I use is... below but somehow I cannot retirve the values under the Path. Please point out my errors ?
XmlDocument _Document = new XmlDocument ();
_Document.Load (FileName);
XmlElement _Root = _Document.DocumentElement ;
XmlNodeList _NodeList = _Document.GetElementsByTagName
("configuration/userNames/sylesh/add/listGridCustomizations/myListGrid");
if (_NodeList.Count > 0)
{
foreach (XmlNode _Node in _NodeList)
{
List.Add(_Node.Attributes.GetNamedItem ("value").InnerText);
}
}
Any help ? suggestions ?
or if I'm wrong please point out ?
thanks Sylesh
<configuration>
<configsections>
<sectiongroup name="userNames">
<sectiongroup name="sylesh">
<sectiongroup name="listGridCustomizations">
<usernames>
<sylesh>
<add key="IsCustomized" value="false">
<listgridcustomizations><mylistgrid>
<add key="Column0" value="Sylesh0">
<add key="Column1" value="Sylesh1">
<add key="Column2" value="Sylesh2">
<add key="Column3" value="Sylesh3">
<add key="Column4" value="Sylesh4">
<add key="Column5" value="Sylesh5">
<add key="Column6" value="Sylesh6">
<add key="Column7" value="Sylesh7">
<add key="Column8" value="Sylesh8">
<add key="Column9" value="Sylesh9">
<listgridcustomizations><wrwerwer>
<add key="Column0" value="Sylesh0">
<add key="Column1" value="Sylesh1">
<add key="Column2" value="Sylesh2">
<add key="Column3" value="Sylesh3">
<add key="Column4" value="Sylesh4">
<add key="Column5" value="Sylesh5">
<add key="Column6" value="Sylesh6">
<add key="Column7" value="Sylesh7">
<add key="Column8" value="Sylesh8">
<add key="Column9" value="Sylesh9">
Thanks
Sylesh
Sylesh
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