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you're welcome.
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Go with Gideon not Luc.
Exceptions are for exceptional situations ie. events that you cannot control and would probably lead to the program halting. The one you describe is not exceptional i.e. it's one that depends on the logic of your code rather than something outside of it.
But then again I'm just an old fuddy-duddy who thinks that way.
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Hi All,
Iam using FTPWebRequest for downloading the files...
Here, the function is working good. but while downloading the file, if the internet connection goes down, then this program going to throws the exception and end the process. So, in this scenario i want to pause/resume downloading...
How to acheive this...
If anybody knows help me...
thanks
Here my sample code
-------------------
public void Download(string fileName)
{
//Desc: To download the file from the ftp server
FtpWebRequest reqFTP;
try
{
//fileName = <<Name of the file to be createdNeed not name on FTP server. name name()>>
FileStream outputStream = new FileStream(downloadPath + "\\" + fileName, FileMode.Create);
reqFTP = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://" + ftpServerIP + ftpPath + "/" + fileName));
reqFTP.Method = WebRequestMethods.Ftp.DownloadFile;
reqFTP.UseBinary = true;
reqFTP.Credentials = new NetworkCredential(ftpUserID, ftpPassword);
FtpWebResponse response = (FtpWebResponse)reqFTP.GetResponse();
Stream ftpStream = response.GetResponseStream();
long cl = response.ContentLength;
int bufferSize = 2048;
int readCount;
byte[] buffer = new byte[bufferSize];
readCount = ftpStream.Read(buffer, 0, bufferSize);
while (readCount > 0)
{
outputStream.Write(buffer, 0, readCount);
readCount = ftpStream.Read(buffer, 0, bufferSize);
}
reqFTP.Abort();
ftpStream.Close();
outputStream.Close();
response.Close();
}
catch (Exception ex)
{
Utils.Write(ex.Message);
}
}
Thanks & Regards
Kumaran
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You can't pause and resume the download, but you can start a new download and start it from a certain point. Have a look at the ContentOffset property of the FtpWebRequest object. Also you can find examples of this just by Googling for "ftpwebrequest resume download".
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I cant get it right... why this doesnt work :S:S
string b = "3.12312123";
if ((b[0] == '2' || b[0] == '3' || b[0] == '4' || b[0] == '5') && ((textBox2.Text != "703") || (textBox2.Text != "733")))
{
this.Text = "OK";
}
else
{
this.Text = "NOT OK!";
}
Any ideas?
Regards,
Matjaž
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I can't be sure what you mean by not working, but that condition will always be true because of this:
((textBox2.Text != "703") || (textBox2.Text != "733"))
The textBox2 text will never be equal to both 703 and 733.
As an aside, you seem to be doing number comparisons, so I would recommend using number variables instead of strings. You could then test (b >= 2 && b < 6)
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Okeeei...
So, i want to check... if its enetered only 703 or 733... BESIDES that the b starts with 2,3,4 or 5.
I really dont know how to make this thing to work... maybe i jsut have a bad day and am a bit confused... but yet again... i dont understand it
Please help? :/
Regards,
Matjaž
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Matjaž Grahek wrote: i want to check... if its enetered only 703 or 733
I have no idea what the condition is.
a) Do you want this.text = "OK" if text = 703 or 733?
b) or do you want this.text = "Not Ok!" if text = 703 or 733?
int textVal = 0;
int.tryparse(textbox2.text, out textVal);
if(textVal == 703 || textVal==733)
{
this.Text = "ok";
this.Text = "Not Ok";
}
Matjaž Grahek wrote: b starts with 2,3,4 or 5
here is a simple solution to that:
int val = 0;
int.tryparse(b[0].ToString(), out val)
this should help,
Prateek
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This code
((textBox2.Text != "703") || (textBox2.Text != "733"))
will always be true
Regards,
Lev
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well,
((textBox2.Text != "703") || (textBox2.Text != "733"))
will always evaluate to true for starters.
Regards,
Rob Philpott.
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Hi,
if you don't understand why a statement behaves the way it does, then the only good advice is to write simpler statements. Why do you insist on putting everything in a single line? Chop it into smaller pieces and look at the intermediate values, that will help you understand if and how it works.
As for the 703/733 thing, as all the others already told you, that cannot possibly be what you intended. For what value do you think it will evaluate to false?
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Well, my intention was ...
If the first character of the string was 2,3,4 or 5 the it should also check the textbox if there is entered any of the two mentioned values (703 or 733).
Ok, looking at it this way... maybe it could work with two ifs...
Regards,
Matjaž
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if (b[0] == '2' || b[0] == '3' || b[0] == '4' || b[0] == '5')
if((textBox2.Text != "703") || (textBox2.Text != "733"))
{
this.Text = "OK";
}
else
{
this.Text = "NI OK!";
}
ok... this doesnt work either:S
Regards,
Matjaž
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Matjaž Grahek wrote: ((textBox2.Text != "703") || (textBox2.Text != "733"))
Guy, for the last time, this will ALWAYS evaluate to True. How about change that "or" to an "and"??
if ((textbox2.Text != "703") && (textbox2.Text != "733"))
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It doesn't work because you haven't changed the logic.
Scott P.
"Simplicity carried to the extreme becomes elegance."
-Jon Franklin
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class Program {
static void Main(string[] args) {
string b = "3.12312123";
if ((b[0] == '2' || b[0] == '3' || b[0] == '4' || b[0] == '5') && ((args[0] == "703") || (args[0]== "733"))) {
Console.WriteLine("OK");
} else {
Console.WriteLine("NOT OK!");
}
}
}
Merry Christmas.
"Simplicity carried to the extreme becomes elegance."
-Jon Franklin
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Your problem displays the most common failure of beginning programmers -- mixing their 'AND' and their 'OR' logic.
You also need to think of how to address your other requirement that the text begin with 2,3,4, or 5.
A possible solution is first to write what you want out in text
if b starts with a valid number and textbox contains valid numbers then it's ok.
That leads to code such as this:
string b = "3.12321212";
List<char> validValues = new List<char> { '2', '3', '4', '5' };
List<string> validInput = new List<string> { "703", "733" };
textbox1.Text = "Not OK";
if ( validValues.Contains( b[0] ) && validInput.Contains( texbox.Text ) )
{
textbox1.Text = "OK";
}
Another way you can also address this problem is with RegEx but I don't have the time to figure out the pattern.
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Ok... thank you all for your answers. Will try this tommorow. Again, thanks for your patience and the will to help.
Good night
Regards,
Matjaž
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Hello
I have just updated a control in my project and cannot access the Design panel because of teh following error:
ResX file Could not load file or assembly 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6' or one of its dependencies. The system cannot find the file specified. Line 7585, position 5. cannot be parsed. ---> System.Xml.XmlException: Could not load file or assembly 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6' or one of its dependencies. The system cannot find the file specified. Line 7585, position 5. ---> System.IO.FileNotFoundException: Could not load file or assembly 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6' or one of its dependencies. The system cannot find the file specified.
File name: 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6'
Where do i delete the bad reference?
The program works but i cannot edit the GUI because of the error.
I am using VS2008 SP1
is there a workaround?
Thanks
Have a nice Day
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Go to the solution explorer, and look at the properties of the reference to the Xceed library. It should have a property called "Specific Version". Set the property to false and rebuild.
If it's a custom library, then check wether the ResX is read-only. I've had some issues with the Interop-toolkit on the generation of resource-files (binary resource not checked out by sourcesafe and being readonly)
Good luck
I are troll
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When I build a project by visual studio 2008, and then copy to a computer equibed with windows XP to run it, It have errors, So I want to know how to confugation to get the release version of my project?
Error message:
The application initialization(0xc0000135)failure, Click OK to close it
I searching in google but didn't find a answer, Maybe I'm a beginner, 
Addition: My question is how to confugation to make the final program run in a machine without .Net framwork?
modified on Thursday, December 18, 2008 10:28 AM
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I'm sorry to post such a simple question in this, but I'm eagar to know the answer, thank you
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Wait more t hen 4 minutes before you post again how eager or urgent it is. If someone here wants to help or knows, they will reply. Otherwise, start hitting google for an answer.
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Hi,
If you want any help you will need to let us know exactly what error message you see and when you see it.
Alan.
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