C#

private int x,y;

private void Form1_MouseDown(object sender, MouseEventArgs e)
{
    x =e.X;
    y =e.Y;
}

private void Form1_MouseUp(object sender, MouseEventArgs e)
{
     if (x == e.X && y == e.Y)
     {
        contextMenuStrip1.Show(this, e.X, e.Y);
     }
}

baranils wrote:

HOW to control the AUTOMATIC popup of a contextmenustrip

public Customer(int id, string name, string city) 
            { 
                Id = id;
                Name = name;
                City = city;
            }

List<Customer> new List<Customer> {
                  new Customer(1, "Dave", "Sarasota"),
                  new Customer(2, "John", "Tampa"),
                  new Customer(3, "Abe", "Miami")
               };

Gareth H wrote:

Are you trying to build a List of Customers?

var customers = new List<Customer>()
{
    new Customer() { Id = 0, Name = "Dave", City = "Sarasota" },
    // ...
};

var customers = new[]
{
    new { Id = 0, Name = "Dave", City = "Sarasota" },
    new { Id = 1, Name = "Ed", City = "London" },
};
foreach (var customer in customers)
{
    Console.WriteLine("{0} [{1}]", customer.Name, customer.City);
}

List<article> ListResult = ListArticle.FindAll(delegate(Article art)
{
   for (int i = 0; i < art.Component<code>s</code>.Count; i++)
   {
      return art.Component<code>s</code>[i].Quantity.Equals(20);
   }

  <code>return false;</code> // Otherwise "not all code paths return a value
});</article>