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So the client is someone who messed up ? I mean, surely there's a link between two european countries using the same word to mean different things ?
Christian Graus - Microsoft MVP - C++
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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Are all the variables strings?
Also, it would be better if you didn't inject values into the SQL command as it can lead to SQL Injection Attacks.
sqlSQL = "UPDATE [IBAX].[dbo].[klanten] "+
"SET [klantOndNr] = @klantOndNr, "+
"[klantNaam] = @klantNaam";
mySqlCommand.CommandText = strSQL;
mySqlCommand.Parameters.AddWithValue("@klantOndNr", klantOndNr);
mySqlCommand.Parameters.AddWithValue("@klantNaam", klantNaam);
If you restructure as above, you might find your error easier to find (if it doesn't fix it) AND the security of your application improved.
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I've changed my code to what you suggested and it works.
Thanks !
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HI All,
I am trying to put together a print function but I am having some trouble with it. I have looked at numerous code and have tried to put my own together but I getthe following error message, "Object not reference not set to an instance of an object". I think I know where the problem is but do't know how to fix it.
<br />
public partial class Orders : Form<br />
{<br />
<br />
private PrintDocument printDoc = new PrintDocument();<br />
private PageSettings pgSettings = new PageSettings();<br />
private PrinterSettings prtSettings = new PrinterSettings();<br />
<br />
<br />
<br />
<br />
<br />
<br />
public Orders()<br />
{<br />
MenuItem fileMenuItem = new MenuItem("&File");<br />
MenuItem filePageSetupMenuItem = new MenuItem("Page Set&up...", new EventHandler(filePageSetupMenuItem_Click));<br />
MenuItem filePrintPreviewMenuItem = new MenuItem("Print Pre&view", new EventHandler(filePrintPreviewMenuItem_Click));<br />
MenuItem filePrintMenuItem = new MenuItem("&Print...", new EventHandler(filePrintMenuItem_Click), Shortcut.CtrlP);<br />
<br />
fileMenuItem.MenuItems.Add(filePageSetupMenuItem);<br />
fileMenuItem.MenuItems.Add(filePrintPreviewMenuItem);<br />
fileMenuItem.MenuItems.Add(filePrintMenuItem);<br />
this.Menu = new MainMenu();<br />
this.Menu.MenuItems.Add(fileMenuItem);<br />
printDoc.PrintPage += new PrintPageEventHandler(printDoc_PrintPage);<br />
<br />
InitializeComponent();<br />
}<br />
<br />
#region Printing Code<br />
<br />
private void filePrintMenuItem_Click(Object sender, EventArgs e)<br />
{<br />
printDoc.DefaultPageSettings = pgSettings;<br />
PrintDialog dlg = new PrintDialog();<br />
dlg.Document = printDoc;<br />
if (dlg.ShowDialog() == DialogResult.OK)<br />
{<br />
printDoc.Print();<br />
}<br />
}<br />
private void filePrintPreviewMenuItem_Click(Object sender, EventArgs e)<br />
{<br />
try<br />
{<br />
<br />
PrintPreviewDialog dlg = new PrintPreviewDialog();<br />
dlg.Document = printDoc;<br />
dlg.FormBorderStyle = FormBorderStyle.Fixed3D;<br />
dlg.SetBounds(20, 20, this.Width, this.Height);<br />
dlg.ShowDialog();<br />
}<br />
catch (Exception ex)<br />
{<br />
MessageBox.Show(ex.Message.ToString());<br />
}<br />
<br />
<br />
<br />
}<br />
private void filePageSetupMenuItem_Click(Object sender, EventArgs e)<br />
{<br />
PageSetupDialog pageSetupDialog = new PageSetupDialog();<br />
pageSetupDialog.PageSettings = pgSettings;<br />
pageSetupDialog.PrinterSettings = prtSettings;<br />
pageSetupDialog.AllowOrientation = true;<br />
pageSetupDialog.AllowMargins = true;<br />
pageSetupDialog.ShowDialog();<br />
}<br />
<br />
private void printDoc_PrintPage(Object sender, PrintPageEventArgs e)<br />
{<br />
<br />
DrawAll(e.Graphics);<br />
<br />
}<br />
Problem is in here.
private void DrawAll(Graphics g)<br />
{<br />
RectangleF srcRect = new Rectangle(0, 0, this.BackgroundImage.Width, BackgroundImage.Height);<br />
<br />
Then the rest of the code
<br />
int nWidth = printDoc.PrinterSettings.DefaultPageSettings.PaperSize.Width;<br />
int nHeight = printDoc.PrinterSettings.DefaultPageSettings.PaperSize.Height;<br />
RectangleF desct = new Rectangle(0, 0, nWidth, nHeight / 2);<br />
<br />
g.DrawImage(this.BackgroundImage, desct, srcRect, GraphicsUnit.Pixel);<br />
<br />
float scalex = desct.Width / srcRect.Width;<br />
float scaley = desct.Height / srcRect.Height;<br />
<br />
Pen aPen = new Pen(Brushes.Black, 1);<br />
<br />
for (int i = 0; i < this.Controls.Count; i++)<br />
{<br />
if (Controls[i].GetType() == this.t1TextBox.GetType())<br />
{<br />
TextBox theText = (TextBox)Controls[i];<br />
g.DrawString(theText.Text, theText.Font, Brushes.Black, theText.Bounds.Left * scalex, theText.Bounds.Top * scaley, new StringFormat());<br />
}<br />
if (Controls[i].GetType() == this.groupBox1.GetType())<br />
{<br />
GroupBox theGroup = (GroupBox)Controls[i];<br />
Rectangle aRect = theGroup.Bounds;<br />
g.DrawRectangle(aPen, aRect.Left * scalex, aRect.Top * scaley, aRect.Width * scalex, aRect.Height * scaley);<br />
}<br />
if (Controls[i].GetType() == this.orderDateDateTimePicker.GetType())<br />
{<br />
DateTimePicker aPicker = (DateTimePicker)Controls[i];<br />
g.DrawString(aPicker.Text, aPicker.Font, Brushes.Black, aPicker.Bounds.Left * scalex, aPicker.Bounds.Top * scaley, new StringFormat());<br />
}<br />
if (Controls[i].GetType() == this.comboBox1.GetType())<br />
{<br />
ComboBox theCombo = (ComboBox)Controls[i];<br />
Rectangle cRect = theCombo.Bounds;<br />
g.DrawRectangle(aPen, cRect.Left * scalex, cRect.Top * scaley, cRect.Width * scalex, cRect.Height * scaley);<br />
}<br />
<br />
}<br />
}<br />
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It's quite simple. You have forgotten about initializing BackgroundImage and you get null reference error as long as "null" is a default value of BackgroundImage. Try doing this:
BackgroundImage = new Bitmap(Width, Height);
or sth like that, whatever.
Greetings - Gajatko
Portable.NET is part of DotGNU, a project to build a complete Free Software replacement for .NET - a system that truly belongs to the developers.
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Thanx mate. That seems to have worked. Now, while that seems to have worke fine I have fond yet another problem. My textbox details have gone missng or better yet itisnot moved into the print preview. Is my code missing something? The textboxes are all within a Group Box. My labels are also not printing which probably mean I have not declared them. Correct? f you could ave a look at why my text boxes are not comming through I would greatly appreciate it. Cheers
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Well, I have a deep night here in Poland so I am in a "not responding" state. Maybe tomorow I will be able to help you.
PS. I have noticed following expression in your code:
Controls[i].GetType() == this.t1TextBox.GetType()
Why not use the is operator?
Controls[i] is TextBox
Good Night - Gajatko
Portable.NET is part of DotGNU, a project to build a complete Free Software replacement for .NET - a system that truly belongs to the developers.
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gajatko wrote: deep night here in Poland so I am in a "not responding" state.
 I'll have to remember that and put California in place for Poland if I use the same line 
"Find it your bloody self - immediately!" - Dave Kreskowiak
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Thanx guys but I am still having problems with this one. My Text boxes don't seem to print over. I think it may because they are sitting in the GROUPBOX. Any further Ideas?
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Yes. You are enumarating Form.Controls collection, which doesn't contain controls which are in a groupbox. Controls in a groupbox are in the GroupBox.Controls collection.
About printing a form. Did you try to use the Form.DrawToBitmap method?
Bitmap b = new Bitmap(Width, Height);
this.DrawToBitmap(b, new Rectangle(0, 0, Width, Height));
b.Save("test.png");
b.Dispose();
Greetings - Gajatko
Portable.NET is part of DotGNU, a project to build a complete Free Software replacement for .NET - a system that truly belongs to the developers.
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Thanx mate. I managed to get one of the groupboxs onto the form now. However groupBox1 doesn't seem to be comming over. I have managed to get some code for printing off the codeprojact site which caters for two groupboxes but it doesn't work in my project. Any other ideas?
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i try to write code for create a barcode. i searched in this site for this and found some documents and samples, they show a table for numbers but i couldn't understand clearly. please help me about barcodesss.
signature...
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Can you tell us what you don't understand?
Me: Can you see the "up" arrow?
User:Errr...ummm....no.
Me: Can you see an arrow that points upwards?
User: Oh yes, I see it now!
-Excerpt from a support call taken by me, 08/31/2007
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1- it's not clear that the first digit is not drawn.because some country codes are three digit
2- what is the min and max width of barcode sticks.
3- what is the odd and even standart and which binary numbers will be used.
thanks for your interest..
signature...
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1 & 2 depend on which type of barcode you're trying to create. I'm guessing you're trying to create an EAN barcode given you specify a country code?
You should probably get a copy of Roger Palmer's book if you need more info http://www.paltec.ca/Book.htm[^]
3 - Sorry, I don't understand.
Me: Can you see the "up" arrow?
User:Errr...ummm....no.
Me: Can you see an arrow that points upwards?
User: Oh yes, I see it now!
-Excerpt from a support call taken by me, 08/31/2007
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yes, i am try to code ean13. I will do this for a small shop. which type of barcode do you suggest me? ean8 is appropriate for this stuation?
forthermore, what is you suggestion to solve odd and even numbers.
signature...
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The business I work for uses code39 for most barcodes.
We can read ean however code39 is definitely the easiest to create.
What you will need is the code39 font which is freely available - search on google.
The beauty of code39 is that the only requirement is:
Starts and ends with an asterisk *
Everything between the asterisks is in caps.
For instance if one of our products is bic01 what we do is code it as *BIC01* and simply change the font to code39.
Any barcode reader that can read code 39 will then be able to read this and the code returned will be BIC01.
IN this manner just install the font on the users computer and ensure that your code uses that font.
The disadvantage of ean is that strictly speaking you need to purchase a subset of these barcodes to make sure that no duplicates exists - from experience I can tell you that duplicates do exist.
Trying to create your own barcodes by drawing black lines is asking for trouble - you are much better off buying an ean font(if that is what you really want) than trying to design one - it will cost you much less, in terms of money and bug fixing, in the long term .
You always pass failure on the way to success.
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thanks for your helps.
signature...
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1. added and initialized some components, including radio buttons
// Create and initialize a GroupBox and a radio Button control.
GroupBox groupBox1 = new GroupBox();
RadioButton radio1 = new RadioButton();
RadioButton radio2 = new RadioButton();
groupBox1.Size = new Size(100,100);
groupBox1.Location = new Point(4,24);
groupBox1.FlatStyle = FlatStyle.System;
groupBox1.Text = "Engin";
radio1.Location = new System.Drawing.Point(8,24);
radio1.Size = new Size(50,20);
radio1.Text = "radio1";
radio1.Name="cb9";
radio2.Location = new System.Drawing.Point(8,64);
radio2.Size = new Size(50,20);
radio2.Text = "radio2";
radio1.Name="cb10";
groupBox1.Controls.Add(radio1);
groupBox1.Controls.Add(radio2);
2. in the button click function, added following to detect state
private void btnPF_Click(object sender, EventArgs e)
{
//DETECTING components
foreach(Control c in panel1.Controls)
if (c.Name.Equals("cb1"))
{
CheckBox lb = c as CheckBox;
if (lb.Checked)
{
//MessageBox.Show("cb1 checked", "info");
}
}
else if (c.Name.Equals("cb9"))
{
RadioButton lb = c as RadioButton;
if (lb.Checked)
{
//MessageBox.Show("radio1 checked", "info");
}
}
else if (c.Name.Equals("cb10"))
{
RadioButton lb = c as RadioButton;
if (lb.Checked)
{
//MessageBox.Show("radio2 checked", "info");
}
}
All of the components are detected properly but not the radio buttons
any help is greatly appreciated
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If RadioButtons are contained in a GroupBox which is in a Panel, then they do not appear in the Panel.Controls collection - they are in the GroupBox.Controls collection, regardless they are also inside the Panel. Similarily, controls inside a panel do not appear in the Form.Controls collection.
By the way, I suggest comparing references instead of comparing names of controls, that is, use "c == cb10" instead of "c.Name.Equals("cb10")".
Greetings - Gajatko
Portable.NET is part of DotGNU, a project to build a complete Free Software replacement for .NET - a system that truly belongs to the developers.
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Whenever i am trying to execute a select statement in a ExecuteScalar() i get the exception from subject: Object reference not set to an instance of an object.
My script is:
public int InsertRecordSP(ref invOrdenes orden)
{
Database db = new Database();
try
{
//abro la coneccion y defino el Store Procedure a utilizar
db.open("insertOrder");
//Ingreso los parametros del Store Procedure
db.setParam("lastOrder", orden.getOrden());
//Ejecuto el Store Procedure
return db.executeScalar();
}
catch (DatabaseException de)
{
log.Error("DatabaseException: " + de.Message);
}
finally
{
db.close();
}
return 0;
}
public Database()
{
// set variables
this.host = ConfigurationSettings.AppSettings.Get("sql-host");
this.user = ConfigurationSettings.AppSettings.Get("sql-user");
this.password = ConfigurationSettings.AppSettings.Get("sql-password");
this.database = ConfigurationSettings.AppSettings.Get("sql-database");
// create the SqlConnection object
String source = "server=" + host + ";uid=" + user + ";pwd=" + password + ";database=" + database;
conn = new SqlConnection(source);
}
public void open(string sprocName)
{
try
{
conn.Open();
scmd = new SqlCommand(sprocName, conn);
}
catch (Exception e)
{
throw new DatabaseException(e.Message);
}
}
public int getParam(string paramName)
{
SqlParameter sqlParam = new SqlParameter();
sqlParam.ParameterName = "@" + paramName;
sqlParam.SqlDbType = SqlDbType.Int;
return (int) sqlParam.Value;
}
public int executeScalar()
{
try
{
return (int)scmd.ExecuteScalar();
}
catch (Exception e)
{
throw new DatabaseException(e.Message);
}
}
What i am doing wrong?
Regards, Diego.
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Hi Diego,
you should have a look at the entire exception, not just its Message.
Use ToString() instead.
Luc Pattyn [Forum Guidelines] [My Articles]
this weeks tips:
- make Visual display line numbers: Tools/Options/TextEditor/...
- show exceptions with ToString() to see all information
- before you ask a question here, search CodeProject, then Google
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If the stored procedure insertOrder does what it name suggests, it doesn't return any result at all. The ExecuteScalar method returns null if the query doesn't return a result, so when you try to use the return value, you get that exception.
---
single minded; short sighted; long gone;
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Why is the value of the tags not being read when the code reads System.xml.XmlTextReader.Text property?
Hence within element <column> column 1 is not being read as text
Note: "sample.xml" is not being rendered well. Tried using HTML escape characters to display a sample but it was unsuccessful. See the code below.
using System;
using System.Xml;
namespace ReadXMLfromFile
{
class Class1
{
static void Main(string[] args)
{
XmlTextReader reader = new XmlTextReader("sample.xml");
while (reader.Read())
{
{
switch (reader.NodeType)
{
case XmlNodeType.Element:
Console.Write("<" + reader.Name);
while (reader.MoveToNextAttribute())
Console.Write(" " + reader.Name + "='" + reader.Value + "'");
Console.WriteLine(">");
break;
case XmlNodeType.Text:
Console.WriteLine (reader.Value);
break;
case XmlNodeType. EndElement:
Console.Write("");
break;
}}}}}}
(source: MSDN)
sample.xml
----------
<database schema-name="products">
<column data-type="text" name="Code" pk="true" fkreferences="Product.Code"> column 1
<column data-type="int" name="Qty"> column 2
<column data-type="currency" name="CostPrice"> column 3
<table name="ProductsInStock"> </table>
<column data-type="text" name="ProductID" pk="true"> column 1
<column data-type="text" name="Description"> column 2
<table name="Product"> </table>
------------------
-- modified at 13:26 Saturday 29th September, 2007
-- modified at 5:24 Sunday 30th September, 2007
-- modified at 5:26 Sunday 30th September, 2007
<div class="ForumSig">Jon</div>
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SqlDataReader read = cmd.ExecuteReader();
read.Read();
photo.Visible = false;
if (read["newsPhoto"] != DBNull.Value)
{
photo.Visible = true;
photo.ImageUrl = "retriveImage.aspx?id=" + read["newId"].ToString();
}
this my code to display image
but all time enter this if statment either i upload the image or not all time he enter if statment ... where the problem ?????
Palestine
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