C# Discussion Boards - CodeProject

27-Jun-07 14:45

Hi,

I have no experience with this whatsoever, but I would suggest you try

... set { if (!DesignMode) Enabled=!value; }

rationale: the code gets executed by the Designer, so you are actually asking to use
the Control to enable/disable itself. My small addition leaves the Enabled property unchanged
while inside Designer.

Smile | :)

Luc Pattyn

[My Articles] [Forum Guidelines]

XML in C#

Kris10027-Jun-07 13:12

Kris100

27-Jun-07 13:12

Hello Coders!
This is quite a general question, I’m just looking for a point in the right direction
Is there any way you can “view” an xml document on a C# Form? By this I mean each element shown on various controls and then a next and previous button to cycle through the XML Nodes?
i have tried various things with XMLDocument, XMLNode and XMLElement but have had no avail, and i was just wondering if there was a set way to do it. The XML file contains Portfolio items that have a name, description and an image link.
Thanks for any help
Kris

max2929727-Jun-07 13:34

27-Jun-07 13:34

I don't know a lot about XML in C#, but since the XML file is encoded using ASCII you should be able to store the xml file in a string then filter it out. That probably doesn't help, but it might work.

-----
*** Never give me an answer having anything to do with Visual Studio. I don't have this because I have two computers, one being my dad's mac, which is connected to the internet, the other being my pc, which is, sadly, not connected to the internet. The setup for the Visual C# program I think is called a "bootstrap" program, and it needs to connect to the internet to install the program. THEREFORE I cannot install this program onto my pc.***

Amit Kumar G27-Jun-07 13:49

Amit Kumar G

27-Jun-07 13:49

I am not very clear with your question. But it seems like you want to populate node values in controls. If i am correct then, you can use Xpath and it is pretty straightforward.

In case you need any source code please let me know...

Thanks
Amit

Christian Graus27-Jun-07 14:01

Christian Graus

27-Jun-07 14:01

One option is to host IE as a control, it displays XML with +/- buttons for the parent nodes.

Otherwise, you need to write your own control, or search the web. The classes you mention are for iterating over XML, and they work just fine, they have nothing to do with displaying it, however.

Christian Graus - Microsoft MVP - C++

"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

Mark Greenwood27-Jun-07 14:58

Mark Greenwood

27-Jun-07 14:58

Use this control

http://www.codeproject.com/cs/miscctrl/Siepe_XmlTreeView.asp[^]

You just throw an XmlDocument at it and it shows all the nodes as a tree style control

I've used it - it has editing etc built in

Mark.

Kris10028-Jun-07 2:39

Kris100

28-Jun-07 2:39

Cheers for the replies guys!

Sorry, I think i was being a bit vague before. What I’m attempting to do is take an XML file that is structured like so:-

<portfolio>
<Item>
<Title>Title</Title>
<Description>Description</summaryDescription>
<Image>imageURL</Image>
</Item>

<Item>
<Title>Title</Title>
<Description>Description</summaryDescription>
<Image>imageURL</Image>
</Item>

...etc

</portfolio>

and displaying the info in separate controls...to the Title in a Textbox and the Image in an Image etc. Then, using 2 buttons, cycle through (left and right) through the items.

its getting the XML into the program I’m having difficulty with, what I want to do is load each Item into an object instance, then put those instances into an ArrayList or something. I’m very new to the .net framework and have tried different things but getting nowhere.

any further help would be fantasic
Thanks again

Kris

max2929728-Jun-07 11:55

28-Jun-07 11:55

Okay, now that I am learned in the art of XML in C# Wink | ;)

, here's some code:

using System;<br />
using System.IO;<br />
using System.Xml;<br />
using System.Collections;<br />
<br />
class Run {<br />
   static void Main() {<br />
      XmlTextReader reader = new XmlTextReader("file.xml");<br />
      <br />
      ArrayList titles = new ArrayList();<br />
      ArrayList descriptions = new ArrayList();<br />
      ArrayList images = new ArrayList();<br />
      <br />
      reader.MoveToContent();<br />
      while (reader.Read()) {<br />
         if (reader.NodeType == XmlNodeType.Element) {<br />
            switch (reader.Name) {<br />
               case "Title":<br />
                  titles.Add(reader.ReadString());<br />
                  break;<br />
               case "Description":<br />
                  descriptions.Add(reader.ReadString());<br />
                  break;<br />
               case "Image":<br />
                  images.Add(reader.ReadString());<br />
                  break;<br />
            }<br />
         }<br />
      }<br />
      <br />
      for (int a = 0; a < titles.Count; a++) {<br />
         Console.WriteLine("-----" + titles[a] + "-----");<br />
         Console.WriteLine(descriptions[a]);<br />
         Console.WriteLine("Image: " + images[a]);<br />
         Console.WriteLine();<br />
      }<br />
   }<br />
}

There 'ya go! This code gathers all the data and seperates it into ArrayLists, then writes them to the console. To do what you are speaking of, all you have to do is...

Create your two textboxes, an imagebox (I think that's what it's called) and two buttons
Create an index integer (e.g. int index = 0;)
For the Click event of the next button, increase the index field by one and set the properties of the textboxes and imagebox to the data in the ArrayLists. (e.g. titleBox.Text = titles[index]; descriptionBox.Text = descriptions[index]; etc.)
For the Click event of the back button, do the same thing, except decrease the index field
Don't forget - if index is greater than titles.Count, set index to zero, and if index < 0, set index to titles.Count

That should do it.

max2929728-Jun-07 12:22

28-Jun-07 12:22

Okay, here's the finished code:

using System;<br />
using System.Windows.Forms;<br />
using System.Drawing;<br />
using System.Xml;<br />
using System.Collections;<br />
<br />
class Run : Form {<br />
   ArrayList titles;<br />
   ArrayList descriptions;<br />
   ArrayList images;<br />
   int index;<br />
   <br />
   TextBox titleBox;<br />
   TextBox descriptionBox;<br />
    PictureBox imageBox;<br />
   Button nextButton;<br />
   Button prevButton;<br />
   <br />
   public Run() {<br />
      XmlTextReader reader = new XmlTextReader("file.xml");<br />
      <br />
      index = 0;<br />
      titles = new ArrayList();<br />
      descriptions = new ArrayList();<br />
      images = new ArrayList();<br />
      <br />
      reader.MoveToContent();<br />
      while (reader.Read()) {<br />
         if (reader.NodeType == XmlNodeType.Element) {<br />
            switch (reader.Name) {<br />
               case "Title":<br />
                  titles.Add(reader.ReadString());<br />
                  break;<br />
               case "Description":<br />
                  descriptions.Add(reader.ReadString());<br />
                  break;<br />
               case "Image":<br />
                  images.Add(reader.ReadString());<br />
                  break;<br />
            }<br />
         }<br />
      }<br />
      <br />
      reader.Close();<br />
      <br />
      this.Size = new Size(520, 430);<br />
      <br />
      titleBox = new TextBox();<br />
      titleBox.Text = (string)titles[index];<br />
      titleBox.Location = new Point(5, 5);<br />
      titleBox.Size = new Size(300, 25);<br />
      this.Controls.Add(titleBox);<br />
      <br />
      descriptionBox = new TextBox();<br />
      descriptionBox.Text = (string)descriptions[index];<br />
      descriptionBox.Multiline = true;<br />
      descriptionBox.Location = new Point(5, 50);<br />
      descriptionBox.Size = new Size(300, 300);<br />
      this.Controls.Add(descriptionBox);<br />
      <br />
      imageBox = new PictureBox();<br />
      imageBox.Image = Image.FromFile((string)images[index]);<br />
      imageBox.Location = new Point(310, 50);<br />
      imageBox.Size = new Size(100, 100);<br />
      this.Controls.Add(imageBox);<br />
      <br />
      prevButton = new Button();<br />
      prevButton.Text = "<--";<br />
      prevButton.Location = new Point(5, 350);<br />
      prevButton.Click += new EventHandler(UpdateInfo);<br />
      this.Controls.Add(prevButton);<br />
      <br />
      nextButton = new Button();<br />
      nextButton.Text = "-->";<br />
      nextButton.Location = new Point(90, 350);<br />
      nextButton.Click += new EventHandler(UpdateInfo);<br />
      this.Controls.Add(nextButton);<br />
   }<br />
   <br />
   public void UpdateInfo(object sender, EventArgs e) {<br />
      if (((Button)sender).Text == "-->") {<br />
         index++;<br />
         if (index >= titles.Count)<br />
            index = 0;<br />
      } else {<br />
         index--;<br />
         if (index < 0)<br />
            index = titles.Count-1;<br />
      }<br />
      <br />
      titleBox.Text = (string)titles[index];<br />
      descriptionBox.Text = (string)descriptions[index];<br />
      imageBox.Image = Image.FromFile((string)images[index]);<br />
   }<br />
   <br />
   static void Main() {<br />
      Application.EnableVisualStyles();<br />
      Application.Run(new Run());<br />
   }<br />
}

I tested it, and it works. Just change the name of the xml file to "file.xml".

Application Properties?

max2929727-Jun-07 12:51

27-Jun-07 12:51

When you right click on an .exe and go to the Version tab (I think that's what it's called), There are several properties of the application that are visible; they are:

File Version
Description
Copyright
Assembly Version
Internal Name
Language
Original File Name
Product Version

Are there options in csc.exe that let you alter these? I couldn't find any when I did csc -?.

Oh yeah, one more thing; When I want to open a file with a program I just created, I right-click the file and press "Open With...". My program is shown in the dialog box that pops up, but all you see is its icon (the default icon) with no text to the right. How do I set the text that is supposed to be there?

J$27-Jun-07 13:27

27-Jun-07 13:27

max29297 wrote:
When you right click on an .exe and go to the Version tab (I think that's what it's called), There are several properties of the application that are visible; they are:

* File Version
* Description
* Copyright
* Assembly Version
* Internal Name
* Language
* Original File Name
* Product Version

You can change those values in your AssemblyInfo.cs (or .vb) file. If you look in your solution explorer, expand the "Properties" folder, you should find it there.

max2929727-Jun-07 13:31

27-Jun-07 13:31

I don't think you read my sig Wink | ;)

Thanks though, I have some other people's AssemblyInfo.cs files from downloading projects from articles. I can figure it out from there

Luc Pattyn27-Jun-07 14:28

27-Jun-07 14:28

Hi Max,

the AssemblyInfo.cs file gets generated automatically by Visual Studio, but
you can create your own, give it a different name, and/or merge it with other files.
Here is a typical example:

using System.Reflection;
using System.Runtime.CompilerServices;
using System.Runtime.InteropServices;

// General Information about an assembly is controlled through the following 
// set of attributes. Change these attribute values to modify the information
// associated with an assembly.
[assembly: AssemblyTitle("TrayIconBuster")]
[assembly: AssemblyDescription("")]
[assembly: AssemblyConfiguration("")]
[assembly: AssemblyCompany("")]
[assembly: AssemblyProduct("TrayIconBuster")]
[assembly: AssemblyCopyright("Copyright ©  2007")]
[assembly: AssemblyTrademark("")]
[assembly: AssemblyCulture("")]

// Setting ComVisible to false makes the types in this assembly not visible 
// to COM components.  If you need to access a type in this assembly from 
// COM, set the ComVisible attribute to true on that type.
[assembly: ComVisible(false)]

// The following GUID is for the ID of the typelib if this project is exposed to COM
[assembly: Guid("fbd90b31-54df-4581-b476-c5fd53c9d279")]

// Version information for an assembly consists of the following four values:
//
//      Major Version
//      Minor Version 
//      Build Number
//      Revision
//
[assembly: AssemblyVersion("1.0.0.0")]
[assembly: AssemblyFileVersion("1.0.0.0")]

Luc Pattyn

[My Articles] [Forum Guidelines]

Luc Pattyn27-Jun-07 14:37

Info about sound from microphone

27-Jun-07 14:37

Hi Max,

to add a file type with description, use Windows Explorer, Tools, Folder Options,
File Types, New, Advanced, and enter the required information.

BTW: you can add/remove/changeorder the fields shown in Windows Explorer through
View, Choose Details. Some of that info is fetched from the file itself, such as
"program version number" for an .EXE, or "date photo taken" for a .JPEG file (from
a camera that provides such info).

Smile | :)

Luc Pattyn

[My Articles] [Forum Guidelines]

Joseph133727-Jun-07 12:13

Joseph1337

27-Jun-07 12:13

Hi
I have a problem. How can I get detailed info about sound from the microphone - the info like the 'jumping bars' in winamp, amplitude, etc. I want to make a voice recognition program using a neural net, but need info about the sound.

Thanks for help

Re: Info about sound from microphone

Christian Graus27-Jun-07 14:03

Christian Graus

27-Jun-07 14:03

Those 'jumping bars' are just examining the wav file for increases in amplitude.

I'm not sure exactly how you examine data as it comes in, but I'm sure the answer will involve DirectShow, which is in the platform SDK.

Christian Graus - Microsoft MVP - C++

"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

Re: Info about sound from microphone

Luc Pattyn27-Jun-07 14:53