C# Discussion Boards - CodeProject

30-Jan-07 21:23

Hello Friends,

I want to know how to use assembly which is registered in GAC(Global Assembly Cache).

I have Created an assembly name dellMe.dll and i have registered it with same name but different

version 1.0.0.0 abd 1.0.0.1. Can i load the any one of the assembly at runtime.

Basically, i want to know how to do this refering of assembly in our C#.Net application.

Any Example will be helpfull.

Thanks In Advance.

Rahul Kulkarni

jdkulkarni30-Jan-07 22:18

30-Jan-07 22:18

You can do it using reflection.

Assembly asm = Assembly.Load("System.Data, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089");

Jayant D. Kulkarni
Brainbench Certified Software Engineer in C#, ASP.NET, .NET Framework and ADO.NET

Rahul.RK30-Jan-07 23:20

30-Jan-07 23:20

For this i have to copy the assembly. Right?

how can i keep different versions of assembly of same name?

Thanks.

Rahul Kulkarni

jdkulkarni30-Jan-07 23:29

30-Jan-07 23:29

If you check the code carefully then you will come to know that System.Data is from GAC only. Now I have .NET 1.1 and .NET 2.0 installed on my machine. Both contains System.Data but with different versions. That is the speciality of GAC. You need to create a strong name and change the version. Then you can copy your assembly in GAC. You do not need to copy it to your application.

Jayant D. Kulkarni
Brainbench Certified Software Engineer in C#, ASP.NET, .NET Framework and ADO.NET

Rahul.RK30-Jan-07 23:37

30-Jan-07 23:37

Thanks ....It works nice.

Thank You Very much

Rahul Kulkarni

Rahul.RK31-Jan-07 0:03

31-Jan-07 0:03

As per you said all working fine.

even we can create instatance of the class of the assembly.

How can we call function of that class. It is not giving intellisense.

what is the solution.?

Rahul Kulkarni.

jdkulkarni31-Jan-07 0:16

31-Jan-07 0:16

Can do like this.

Assembly asm = Assembly.Load("System.Data, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089");
            Type[] tps = asm.GetTypes();
            foreach (Type tp in tps)
            {
                if (tp.IsClass)
                {
                    MethodInfo[] methods = tp.GetMethods();
                    object abc = Activator.CreateInstance(tp);
                    if (!methods[0].IsStatic)
                    {
                        methods[0].Invoke(tp, new object[] { });
                    }
                }    
            }

Jayant D. Kulkarni
Brainbench Certified Software Engineer in C#, ASP.NET, .NET Framework and ADO.NET

jdkulkarni31-Jan-07 1:08

31-Jan-07 1:08

Here is a sample code that will open a connection to sql server using reflection.

string connString = "Server = localhost; Database = EmployeePortal; User ID = abc; Password = abc; Trusted_Connection = False;";
            Assembly asm = Assembly.Load("System.Data, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089");
            
            Type[] tps = asm.GetTypes();
            foreach (Type tp in tps)
            {
                if (tp.IsClass)
                {
                    if (tp.Name == "SqlConnection")
                    {
                        Console.WriteLine("Sql connection found...");
                    }
                    MethodInfo[] methods = tp.GetMethods();
                    object abc = null;
                    try
                    {
                         abc = Activator.CreateInstance(tp, connString);
                    }
                    catch (Exception ex)
                    {
                    }
                    foreach (MethodInfo method in methods)
                    {
                        if (tp.Name == "SqlConnection" && method.Name == "Open")
                        {
                            Console.WriteLine(method.Name);
                            method.Invoke(abc, null);
                        }
                    }
                }    
            }

Jayant D. Kulkarni
Brainbench Certified Software Engineer in C#, ASP.NET, .NET Framework and ADO.NET

Rahul.RK31-Jan-07 2:05

31-Jan-07 2:05

Firstly, Thanks.

You helped me alot.

I got the concept you are telling.

On the basis of your example, i tried for messagebox function.

But it is giving me exception "Parameter Missmatch".

I am not getting were do i can function returned value

Rahul Kulkarni

jdkulkarni31-Jan-07 17:13

31-Jan-07 17:13

If you have overloaded methods then you need to check which method you want to execute. Here is the sample code to call MessageBox.Show("Hi").

Assembly winAsm = Assembly.Load("System.Windows.Forms, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089");

            Type[] allTyps = winAsm.GetTypes();
            foreach (Type typ in allTyps)
            {
                if (typ.Name == "MessageBox")
                {
                    Console.WriteLine("MessageBox found...");

                    MethodInfo[] mtds = typ.GetMethods();
                    foreach (MethodInfo mtd in mtds)
                    {
                        if (mtd.Name == "Show")
                        {
                            if (mtd.GetParameters().Length == 1)
                            {
                                mtd.Invoke(typ, new object[] { "Hi!!" });
                            }
                        }
                    }
                }
            }

Jayant D. Kulkarni
Brainbench Certified Software Engineer in C#, ASP.NET, .NET Framework and ADO.NET

Rahul.RK1-Feb-07 19:14

How to capture mouse enter event while left mouse button is clicked?

1-Feb-07 19:14

Thanks very much..

Alvaro Enriquez30-Jan-07 21:18

Re: How to capture mouse enter event while left mouse button is clicked?

30-Jan-07 21:18

Hello! I am developing a GUI and I am having an strange problem. It
should be a very easy thing, but I have been walking around it for a
while. In my Form, I have a picturebox. I want to detect when the
mouse pointer enters the picturebox area WHILE the mouse left button
is pressed.

I have tried mouseenter, mousedown and mousemove events and none of
them are rised when I enter the control area with the mouse pointer
WHILE the left button is clicked!!!

Any ideas?

Thank you very much in advance!

Alvaro

Mircea Puiu31-Jan-07 0:34

Re: How to capture mouse enter event while left mouse button is clicked?

31-Jan-07 0:34

The event you want to treat is fired only if the none of the mouse buttons are pressed.
To overcome this behaviour, treat the MouseMove event of the form like this:

private void Form1_MouseMove(object sender, MouseEventArgs e)
{
	if (e.Button == MouseButtons.Left)
	{
		Point pt = pictureBox1.PointToClient(Cursor.Position);
		Rectangle rc = pictureBox1.ClientRectangle;
		if (rc.Contains(pt))
		{
			// Do what you wanted to do within the MouseEnter event handler
		}
	}
}

where pictureBox1 is your PictureBox object

SkyWalker

Alvaro Enriquez31-Jan-07 1:31

Re: How to capture mouse enter event while left mouse button is clicked?

31-Jan-07 1:31

Hi, Skywalker.

I have tried your solution, but this event is only fired when the mouse is moved in the form, outside the controls (I mean, move it around the background), so as soon as I move my mouse in a picturebox, it is not firing.

I am sorry... maybe trying to simplify the problem I haven't shown the correct enviroment. I will try it again:

I have a form with a panel, and in that panel I have 5 pictureboxes. When the user clicks (and hold the mouse button pressed as if he were dragging) into one of these five pictureboxes, I set a "origin" integer var to 1-5. What I want to do is, when the user moves the mouse with that button pressed and pass over one of the other picturbox, set a "target" integer variable with a value between 1 and 5.

The user could, in example set a origin and drag over several of the other pictureboxes updating the "target" var without release the mouse button.

Any ideas or comments would be very appreciated.

Thank you very much in advance!!!

Alvaro

Mircea Puiu31-Jan-07 2:35

Re: How to capture mouse enter event while left mouse button is clicked?

31-Jan-07 2:35

Believe me, I've tried the code before posting it Smile | :)

MouseMove is fired alright!

SkyWalker

Martin#31-Jan-07 2:49

Martin#

31-Jan-07 2:49

Clever idea! Smile | :)

got my 5

Re: How to capture mouse enter event while left mouse button is clicked?

Mircea Puiu31-Jan-07 3:32

Re: How to capture mouse enter event while left mouse button is clicked?

31-Jan-07 3:32

Vielen Dank Smile | :)

SkyWalker

Alvaro Enriquez31-Jan-07 3:55

Re: How to capture mouse enter event while left mouse button is clicked?

31-Jan-07 3:55

What you are suggesting works in the case you click the left button in the main form, outside the pictureboxes. If you create two pictureboxes: picturebox1 and picturebox2 in your form and assign picturebox1 the mousedown event and the whole form the mousemove event you proposed,you will reproduce my problem. What I want is: clicking in area of the picturebox and holding the button pressed (drag, if you prefer), go to the area of the picturebox2 and obtain the message: "I have gone from 1 to 2" while my mouse button is still pressed.

I hope the code below clarify the issue.

int origin=0;
int target=0;

private void Form1_MouseMove(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
Point pt = pictureBox2.PointToClient(Cursor.Position);
Rectangle rc = pictureBox2.ClientRectangle;
if (rc.Contains(pt))
{
target = 2;
// Do what you wanted to do within the MouseEnter event handler
MessageBox.Show("I have gone from " + origin + " to " + target);
}
}
}

private void pictureBox1_MouseDown(object sender, MouseEventArgs e)
{
origin = 1;
}

Any ideas? Thank you for all your efforts!

Mircea Puiu31-Jan-07 4:59

Re: How to capture mouse enter event while left mouse button is clicked?

31-Jan-07 4:59

So what!
Copy the same code within the MouseMove event associated to the other control you want
( private void OtherPicture_MouseMove(object sender, MouseEventArgs e) )

And if you want a more general approach, then you have to do a little effort, but the idea is the same Smile | :)

Try!

SkyWalker

Martin#31-Jan-07 10:46

Martin#

31-Jan-07 10:46

And it's still clever!
Wink | ;)

Re: How to capture mouse enter event while left mouse button is clicked?

Alvaro Enriquez31-Jan-07 23:15

Re: How to capture mouse enter event while left mouse button is clicked?

31-Jan-07 23:15

OK. I have done what you have recommended, but it is unuseful. I have written then next mousemove event fot both the inkpictures:

private void inkPicture_MouseMove(object sender, MouseEventArgs e)
{
if (dragging)
{
PictureBox pb = (PictureBox)sender;
if (e.Button == MouseButtons.Left)
{
if (pb == pictureBox1)
{
target = 1;
}
else if (pb == pictureBox2)
{
Console.WriteLine("Asigned 2");
}
}
}
}

What I want is to get both the message "Asigned 1" and "Asigned 2" WITHOUT RELEASE THE MOUSE BUTTON, I mean, clicking and holding the mouse button in one of the two pictureboxes and going over the other one with the button still clicked. Please, try it. If you keep the button pressed when you leave the original picturebox, it remains throwing the mousemove event for that picturebox you have just leaved as if you were still in its area. That is my problem, and that is why I cannot detect when entering the new picturebox. I really hope my explanation to be clearly enough this time.

Any ideas?

Thank you very much in advance!!!

Alvaro Enriquez1-Feb-07 0:31