|
Hi there!
I managed to make a service and then made a setup project for it.The set up worked fine on my PC but when i tried to install this service on another PC i came up with an error while trying to start the service "Error:1053 The service did not respond to start or control request in a timely fashion".
This error did not come after 3 minutes rather it came as soon as the service was tried to be started.
Plz help me in this matter.
Regards
Asif Rogers
asifrogers
|
|
|
|
|
Using C# forms and graphic box.
I am looking for help creating a form in which i have a graphic box. In the graphic box I can load an image that is 1024x768 in size. I want to be able to add a graphic and lock it by the x, y cord, on top of the other graphic in a seperate plane. Is this possible and does anyone have any ideas on how to make this easy to code and stable?
Rob
|
|
|
|
|
Is a graphic box a picture box ? If you want to draw images in layers, you need to do it yourself.
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
yes.. its a picture box. The standard in c# VS. But what im trying to do is have two seperate immages float on top of each other, so i can click each seperatly and have seperate objects. The locations will load from a sql db of where to snap to. How can this be done?
|
|
|
|
|
Anonymous wrote:
The standard in c# VS.
Well, the quick and easy way, at least.
Anonymous wrote:
How can this be done?
Like I said, you need to draw the images yourself. Handle OnPaint and draw them there.
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
hi,
i've already added a control with an image in my toolbar but the image disappears when i run my app.. why is that so?
thanks
|
|
|
|
|
I would like to have clients call some kind of an enqueue web method and wait for a server response. I was hoping someone could tell me the correct threading code to accomplish this.
Client > [WebMethod]public string Wait() > [Client thread waits] > Server fires "RETURN" >
Client returns "RETURN"
Anyone know how to do this?
|
|
|
|
|
|
|
Hi
I have Class A with a protected virtual member Method1() and i have another calss Class B inheriting Class A in which i overrided the base class's method Method1() and i also call the base class's Method1() using the base keyword. Now i have another class Class C which inherits Class B and i am overriding Method1(), the problem is now how do i call Class A's Method1() from this class.
<br />
Class A<br />
{<br />
protected virtual Method1()<br />
{}<br />
}<br />
<br />
Class B : Class A<br />
{<br />
protected override Method1()<br />
{<br />
base.Method1()<br />
}<br />
}<br />
<br />
Class C : Class B<br />
{<br />
protected override Method1()<br />
{ <br />
QUESTION: HOW TO CALL CLASS A's METHOD1() HERE. I dont want to call Class B's Method1() but want to call Class A's Method1()<br />
}<br />
}<br />
F1! F1! F1!....plzzz
Regards
Chettu.
|
|
|
|
|
You can't do it directly in C# because B has already overridden Method1. You need to have a protected "forwarding" method in class B that does what you want to. Something like
class B : A
{
protected void ForwardMethod()
{
base.Method1();
}
}
It's possible in C++ though, A::Method1 will do the job.
Regards
Senthil
_____________________________
My Blog | My Articles | WinMacro
|
|
|
|
|
You can't, and it would suck if you could. Looks like C should derive from A.
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
Why would it suck.. i have a case where Class C should inherit Class B and not A isn't this a possible scenario... i guess so....The possible solution i have done is have a method in class B which will call the base method in A. This scenario will hold in events.. where calling the base class is mandatory....
|
|
|
|
|
chettu wrote:
i have a case where Class C should inherit Class B and not A isn't this a possible scenario
No, because if inheritance is optional, how could you count on it in any way ?
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
Hi
This is for a windows application in C#. I am using a PrintDialog and a PrintPreviewDialog. When I go through the PrintDialog my document prints correctly. When I use the PrintPreviewDialog the preview is correct. However when I click the print icon on the Preview dialog the printer only pushes out a blank paper. Is there anything that I need to specify in the PrintPreviewDialog?
Thanks
Kobus
|
|
|
|
|
You are not setting the Document property of the PrintPreviewDialog for sure. Please check.
Live Life King Size
Alomgir Miah
|
|
|
|
|
i am using remote data access for my project. this is my code.
private void button2_Click(object sender, System.EventArgs e)
{
SqlCeConnection cn = null;
SqlCeRemoteDataAccess rda= null;
SqlCeEngine sqlEngine=null;
try
{
button2.Enabled=false;
//Create database if it doesn't already exist
if(!File.Exists("\\My Documents\\Student.sdf"))
{
sqlEngine=new SqlCeEngine( );
sqlEngine.LocalConnectionString="Data Source=\\My Documents\\"+
"Student.sdf;"+
"Password= ;"+
"Encrypt Database=True";
sqlEngine.CreateDatabase();
sqlEngine.Dispose();
}
else
{
//open the connection to the database
cn=new SqlCeConnection("Data Source=\\My Documents\\"+
"Student.sdf; Password=");
cn.Open();
SqlCeCommand cmd=cn.CreateCommand();
//drop table tutorial1_Classlist
cmd.CommandText="DROP TABLE tutorial1Class_list";
cmd.ExecuteNonQuery();
//close the conection
if(cn.State!=ConnectionState.Closed)
{
cn.Close();
}
}
//Instantiate the RDA Object
rda=new SqlCeRemoteDataAccess();
//Connection String to the Sql Server
string remoteConnectString="Provider=SQLOLEDB;"+
"Data Source=IT768P27;"+
"Initial Catalog=Student;"+
"User Id=sa;" +
"Password=";// empty password
rda.InternetLogin="";
rda.InternetPassword="";
rda.InternetUrl="http://IT768P27/StudentRDA/sscesa20.dll";
rda.LocalConnectionString="Data Source=\\My Documents\\"+
"Student.sdf;"+
"SSCE:Database Password=";
rda.Pull("tutorial1Class_list", "Select * from tutorial1Class_list",
remoteConnectString,RdaTrackOption.TrackingOn);
}
catch(SqlCeException sqlex)
{
foreach(SqlCeError sqlError in sqlex.Errors)
{
MessageBox.Show(sqlError.Message,"Error");
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message,"error");
}
finally
{
rda.Dispose();
button2.Enabled=true;
}
}
when i run it in my pocketpc ,it give me error like "sql server ce encountered problems in creating the sql server ce database[...connection string..]..
what should i do.. i c every codeing is all right. can u tell me what is wrong with my connection string?
|
|
|
|
|
I see that no one ever replied to this....I hope you found the answer!
But if not...the RDA connection expects IIS at the receiving end. //MyDocuments// is not a well-formed URL for going to a web server.
However if you have IIS running then at a minumum your web would be something like:
"http://myMachineName/SqlHost" assuming your RDA host connection
is in the web SqlHost.
So you need your host name and web name for a well structured IIS connect to your database.
There are 10 kinds of people in the world.
Those that read binary...
...and those who don't.
|
|
|
|
|
Hi.I need to work with Calendar Control .Can you show me where can I find any good tutorials or examples on this topic .Thank you
|
|
|
|
|
I would suggest that you got voted a 1 for two reasons
1. 'How can I' is not a decent way to head your question, I thought you'd posted the same question twice
2. Google will answer both of these questions in seconds.
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
Hi.Can you show me any tutorial about editing the information of a database which is shown in datagrid.I need to add ,delete,update information interacting only with the grid.Thank you
|
|
|
|
|
Hi!
Im making a form which displays data on a datagrid when i select an item from my dropdownlist. Now my problem is nothing shows up when i choose from my dropdownlist. can someone please check and see if my code is correct because it builds perfectly infact it shows the header but leaves the rest of my queries. Here's parts of the code assuming that my sql queries are correct which i've great confidence that the are:
<br />
DataSet dsCompany = new DataSet();<br />
dsCompany = objComp.fGet_Company();<br />
ddlcomp.DataSource = dsCompany;<br />
ddlcomp.DataTextField = "comp_code";<br />
ddlcomp.DataValueField = "comp_desc";<br />
ddlcomp.DataBind();<br />
ddlcomp.Items.Insert(0,"");<br />
<br />
Session["Comp"] = ddlcomp.SelectedItem.Value;<br />
Session["CompName"] = ddlcomp.SelectedItem.Text;<br />
<br />
if (Session["Comp"].ToString() != "")<br />
{<br />
ddlcomp.Items.FindByValue(Session["Comp"].ToString()).Selected = true; <br />
}<br />
<br />
private void ddlcomp_SelectedIndexChanged(object sender, System.EventArgs e)<br />
{<br />
DataSet dsCol = new DataSet();<br />
dsCol = objCol.GetByClient(ddlcomp.SelectedItem.Value);<br />
<br />
Session["dstSort"] = dsCol;<br />
Session["dtvwSort"] = dsCol.Tables[0].DefaultView;<br />
dgdGrid.DataSource = dsCol;<br />
dgdGrid.DataBind();<br />
}<br />
so...anything wrong with this?
thanx for all your comments, suggestions and reactions!
Kampai!!!
|
|
|
|
|
tatchung wrote:
because it builds perfectly
So what ?
tatchung wrote:
DataSet dsCompany = new DataSet();
dsCompany = objComp.fGet_Company();
this is dumb - the new dataset you created will now go into the queue for garbage collection, as you replaced it righ away with the result of this call.
tatchung wrote:
ddlcomp.DataSource = dsCompany;
ddlcomp.DataTextField = "comp_code";
ddlcomp.DataValueField = "comp_desc";
ddlcomp.DataBind();
ddlcomp.Items.Insert(0,"");
None of this is in a !IsPOstback block, so it binds every time, and your selection is lost.
tatchung wrote:
Session["Comp"] = ddlcomp.SelectedItem.Value;
Session["CompName"] = ddlcomp.SelectedItem.Text;
These will always be the first item in the list, as you just did a databind and an insert.
tatchung wrote:
dsCol = objCol.GetByClient(ddlcomp.SelectedItem.Value);
Events fire after page load and before prerender. Not knowing where you did the above, I have no idea what the SelectedItem could be at this stage.
tatchung wrote:
DataSet dsCol = new DataSet();
dsCol = objCol.GetByClient(ddlcomp.SelectedItem.Value);
Waste of memory again.
tatchung wrote:
Session["dtvwSort"] = dsCol.Tables[0].DefaultView;
You're shoving a whole table into the session ? You seem to be using session state a lot, is all of this stuff needed on other pages ? AND you shove it in twice, as dstSort and dtvwSort. This is not ASP. Why do you need this information in the session ?
tatchung wrote:
so...anything wrong with this?
The lack of an !IsPOstback is probably your core problem.
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
Like I said its only part of the code. Sori i couldn't post every part of the form its too long. I've an !IsPostBack right below my Page_Load member along with my "pop-up window" code. Oops! I forgot to mention that this form links to a pop-up window...my bad . Ohe yeah the datasets created was meant to draw the data from a class i've made in another form. Darn me for skipping too many information.
Ok so here's the deal this form generates data from a database when i fire the dropdownlist. Along with the results it should display 2 buttons for each row; edit and delete. Now when I click the edit button it redirects to my pop-up window and delete...well it deletes the entire row it is aligned with. Back to my first thread...nothing seems to appear when i choose from my dropdownlist except the headers.
I appologize for any misinformation or rather for lack of information. All your replies are greatly appreciated! Thanx for all your assistance!
Kampai!!!
|
|
|
|
|
tatchung wrote:
I've an !IsPostBack right below my Page_Load member along with my "pop-up window" code.
So the Data binding code is in an !IsPostback block ?
tatchung wrote:
Ohe yeah the datasets created was meant to draw the data from a class i've made in another form. Darn me for skipping too many information.
But why are you stuffing them into the session, and duplicating info into the session ?
I still think nothing appears because you're resetting your data source. Have you stepped through the code in debug mode ?
Christian Graus - Microsoft MVP - C++
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
