C#

PaintEventArgs e = new PaintEventArgs();
// set up e's properties
// ...
OnPaint(e);

Stefan Troschtz wrote:

Simply show form2 by using ShowDialog method.

Stefan Troschtz wrote:

If that is not an option register to the Form.Closed or Form.FormClosed (framework > 1.1) event of form2 and enable your form1.

marwan_siala wrote:

it works, but not the way i need

marwan_siala wrote:

it did not work

class Form2
{
   ....
   private Form1 caller;

   Form2_Init(Form1 cal)
   {
      this.caller = cal;
   }

   Form2_Closing()
   {
      caller.Enabled = true;
   }
}

class Form1
{
   public Form1()
   {}
   public actionToShowForm()
   {
      Form2 form = new Form2(this);
      form.Show(); //or show dialog to avoid all this :S 
      this.Enabled = false;
   }
}

class Form2
{
   private Form1 callerForm;
   public Form2(Form1 caller)
   {
      this.callerForm = caller;
      this.Closing+=new EventHandler(form2_Closing);
   }
   void form2_Closing(object sender, EventArgs e)
   {
      this.callerForm.Enabled = true;
   }
}

class Form1
{   
  public Form1()   {}   

  public actionToShowForm()   
  {      
    Form2 form = new Form2(this);
    form.Closed += new EventHandler(form2_Closed);
    form.Show(); 
    this.Enabled = false;   
  }

  void form2_Closed(object sender, EventArgs e)
  {      
    this.Enabled = true;   
  }
}