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how do i use the print dialog to print the current page. I'm guessing upon return from the print dialog i can check a property which will tell me if "current page" is clicked. but i cant find it for the life of me. barking up the wrong tree?
cheers
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in case anyone is interested, i finally solved it...
if (this.printDialogReport.PrinterSettings.PrintRange == System.Drawing.Printing.PrintRange.CurrentPage)<br />
{<br />
...<br />
}
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Deat all,
How to calculate number of days between two differnt selected dates considering leap year also.
Number of days should are calculate in the code itself,Not in sql.
Please give me some code snippet for all these.
Thanks in advance.
kissy
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this[^] would have been quicker for you.
If you subtract one date from another, you get a TimeSpan
as in
TimeSpan ts = date2 - date1;
Christian Graus - Microsoft MVP - C++
"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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Use DateTime.CompareTo to determine which of your dates is earliest, then substract it from the other using DateTime.Substract to determine the timespan you need.
Standards are great! Everybody should have one!
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string[] stringArray = {"Hello", "World"};<br />
ListViewItem lvi = new ListViewItem(StringArray);<br />
<br />
if(this.listview1.items.contains(lvi))<br />
{<br />
;
}<br />
else<br />
{<br />
this.listview1.items.add(lvi);<br />
this.listview1.update();<br />
}<br />
Why does this code always run in else block when the same Listview item is added into the listview??
Som
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Is it because everytime a new object is created??
What if I want to compare listview items and then add into listviews???`
Som
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Because it doesn't. Even if the contents of the two items are the same, they are two different list view items. They just happen to have the same strings in them. You need to search through the strings inside the items, if that is what you mean.
Christian Graus - Microsoft MVP - C++
"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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Christian Graus wrote: You need to search through the strings inside the items,
Do u mean to say I need to use the 'SubItem' property..??
Then how do we use listview.contains ?
Som
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I'm assuming there's a find method which finds the first item which contains a string, or something like that.
Christian Graus - Microsoft MVP - C++
"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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i asked this question here before too but no answer so i m asking again..that i hav a mdi form which displays a mdi-child form on its load event...it contains various functionality..like view the complete detail of the current user of the datagridview...so on opening this view(mdi-child)form it displayed under the mdi-parent form and also shows its menu items like File,Edit,View etc...and also having an edit button..which displays another(mdi-child)form for editing the record..but the problem is this..it is not displaying under mdi-parent form and not showing the mdi-parent's menu item..even it also hides the start menu bar...so please help me how to call a mdi-child form from another mdi-child form
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What happens if you create a method on the mdi-parent that opens the edit form? By using this technique the two forms are opened the same way. If you still get the same behavior the problem must be related to how you have set up the two forms.
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Christian Wikander wrote: What happens if you create a method on the mdi-parent that opens the edit form?
but i dont want to open the edit form from mdi-parent form..i want to opent the form from that view form and i coded like..
up.MdiParent = this.MdiParent;
up.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
up.Show();
so please help
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Well, you need to start experimenting to find the source of the error. Then you can judge if you should try to solve it or try to find another acceptable solution. Just sitting there waiting for answers will get you nowhere.
Another thing you can try is to comment out the line where you set FormBorderStyle.
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Christian Wikander wrote: Just sitting there waiting for answers will get you nowhere.
thanx for suggestion....and telling me the truth
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i agree with this.
create your midi forms on the midi parent... always.
if you want to create/call from another midi child, create an event on the midi child, something like "CreateMidiChild", and when the event is triggered the midi parent which will be subscribed to this event can create the new child for you.
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thanxxx...my problem is solved now
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Hi
I have one user defined service pack in this service pack was good running in windows XP os but in windows vista its not running why?pplease tell me how to solve this problem!!
*****THANKS N ADVANCE****
Mathen.K
(I WILL TRY MY LEVEL BEST )
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What on earth is your question ? What do you mean by service pack ? What do you mean by 'not running' ? Is this even a C# question ?
Christian Graus - Microsoft MVP - C++
"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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hi thanks to your replay!!
Service pack means its one exe file its also generate Microsoft visual studio.in this Exe was executing in XP but in vista its not ..this is my problem!!
*****THANKS N ADVANCE****
Mathen.K
(I WILL TRY MY LEVEL BEST )
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OK, first of all, when you build an exe, it's NOT called a service pack.
Second, if it doesn't run in vista, you need to work out at what point it fails, and then you can work out why.
Christian Graus - Microsoft MVP - C++
"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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hi wen i ran that application ..its showing one dialog msg.actually this was partially developed C++.
Debug Error!
Program: C:\program files\driv\j21.4.2\bin\javaw.exe
Module :\citi\apps\EDCJNI.dll
File:
Run-Time Check Failure #0-The value of ESP was not properly saved across a function call. This is usually a result of calling a function declared with one calling convention with a function pointer with a different calling conversion.
what kind of error this!!please tell me how to solve it!!?
*****THANKS N ADVANCE****
Mathen.K
(I WILL TRY MY LEVEL BEST )
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Read this[^] to understand how I found answers here[^].
Christian Graus - Microsoft MVP - C++
"also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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Hi,
I am using client server architecture. I want to stop or start some process which is running on Client Machine.
How can I do this?
Regards,
sjs4u
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