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toxcct wrote: Pan San wrote:
没有更好，只有看哪个更适合你
you seem to have a serious problem with english, don't you ?!
toxcct,
The poster said (according to http://www.worldlingo.com/[^]), "Not better, only then looked which suits you."
"We make a living by what we get, we make a life by what we give." --Winston Churchill
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I think you are a clever boy!
My English is really poor,although I have studied English 13 years ,but I found it have no effect to me.
Sorry to say,I haven't pass the CET6 exam,by the way ,I'm a Master of computer,I still should to study English,it's boring.when I want to find some technique articles,it's hard for me to read English articles.
From this sentence I have wrote,you can sure my English is so poor,isn't it?
But you should know,I'm not a person who come from Europe or other country which said English.I think you had know where I from,lukily to say ,I come from a great and beautiful country.
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Software_Specialist wrote: which one is better and why ?
What is better, a fork or a spoon ? I guess it depends on the task at hand.
Software_Specialist wrote: I knw how to program over C++.NET but i am new over VC++..
How do you mean ? C++.NET is standard C++, with .NET extensions. If you know C++.NET, you know at least some C++.
Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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Then for what tasks C++.NET is better and for which tasks VC++ is better.
Dont you think VC++ is lot more complicated than C++.NET ?
And if not then give me a simple windows based application example, explaining how you would achieve in both.
Obviously i know C++ but on .NET platform. So i am keen to know which is better and what industry needs more these days ...
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Clickety[^]
Press: 1500 to 2,200 messages in just 6 days? How's that possible sir?
Dr.Brad :Well,I just replied to everything Graus did and then argued with Negus for a bit.
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What do you need exactly?
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Hi all.
I write code:
<br />
CStringArray a1,a2;<br />
. . . . .<br />
. . . . . <br />
for(int i=0; i < a1.GetSize(); i++)<br />
a2.Add(a1.GetAt(i));<br />
<br />
a2.RemoveAt(Sel);
a2.FreeExtra();<br />
<br />
if(a1.GetUpperBound() == a2.GetUpperBound())<br />
return;
My progrum tell me that this string are equal.
Can help?
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david bagaturia wrote: if(a1.GetUpperBound() == a2.GetUpperBound())
return;//and it come here
I can see there are no elements in a2. Probably, there are no elements in a1,too. In this case
GetUpperBound returns -1. Which cause equality between these two.
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So, what was problem? Were these two arrays are same ?
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I agree with prasad_som. This is easy to test without your mystery ". . . ." lines of code:
CStringArray a1,a2;
a1.Add(L"String 1");
a1.Add(L"String 2");
a1.Add(L"String 3");
for(int i=0; i < a1.GetSize(); i++)
a2.Add(a1.GetAt(i));
a2.RemoveAt(1);
a2.FreeExtra();
if(a1.GetUpperBound() == a2.GetUpperBound())
return;
"Great job, team. Head back to base for debriefing and cocktails."
(Spottswoode "Team America")
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Hello,
i have some data from a database, like this:
ID NAME
1 Micheal
2 Thomas
3 Michael
i want to read this from the database and put this data into a listbox.
the listbox entries look like this:
Michael
Thomas
Michael
how can i determine for example if i select the second "Michael" that this is the "Michael" from the database width ID = 3
is it possible to give the listbox-items id numbers like in html???
thanks
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I wouldn't like to compare with HTML, but you can give list box items IDs.
int AddStringWithIDToListBox (CListBox &lb, CString s, DWORD dwID)
{
int nSel = lb.AddString (s);
if (nSel == LB_ERR) return nSel;
return lb.SetItemData (nSel, dwID);
}
You can get the ID at a later time with GetItemData (nSel) etc. The reason for the two step adding, then setting, is that you may have a sort style on your listbox - so insert order != order in list box.
I hope this help,
Iain.
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that works fine!!!
thanks
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Hi ..
I have designed a modal dialog box .. CMyAppDlg ..
If I declare CMyAppDlg * mapp .. code works well ..
If I declare CMyAppDlg mapp .. document pointer crashes ..
Pl help me ..
Thanking you ..
manisha
Manimau
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kulkarni.manisha@rediffmail.com wrote: If I declare CMyAppDlg * mapp .. code works well ..
If I declare CMyAppDlg mapp .. document pointer crashes ..
Need to show some relevent code. What debugger says about crash ? Have you checked call stack ?
kulkarni.manisha@rediffmail.com wrote: Manimau
 ,nice sig.
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kulkarni.manisha@rediffmail.com wrote: Manimau
prasad_som wrote: ,nice sig.
What does that mean?
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brahmma wrote: What does that mean?
In marathi we(children ofcourse) call cat as maternal aunt of tiger( ).
And call her "Manimau".
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I feel really dumb for asking this. For the this equation:
y = x * n
How can I calculate what the smallest integer n that I can multiply the rational number x by so that y also becomes an integer? Can this be done analytically, or will I need an algorithm?
Thanks
Joel Holdsworth
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Could you rephrase the question. Not quite sure what you are trying to do.
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So if x = 12.5, the smallest n that I can multiply it by is 2, if I want an integer value of y (which in this case is 25). Is guess it might get more tricky if x = 3 1/3 or something.
Joel Holdsworth
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In your origional post you referred to x and y as integers. In C/C++ integers have no decimal points, they are always rounded down to the nearest whole number. Perhaps you meant double or float.
As for the problem, divide 1 by the decimal.
1 / ( 12.5 - 12 ) == 2
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Joel Holdsworth wrote: integer n that I can multiply the rational number x by so that y also becomes an integer
n : integer
x : rational
y : value of x * n which must equal to an integer
for this Joel, you must find what is the equivalent fraction of x; i mean, 1.33333 is actually 4/3.
only then you have this, you know n because it equals the denominator of that fraction (here, 3).
but that's not that simple, because is the rational number equates to a too big fraction, you will find dumb values
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y = x * n
Where:
“y” is an integer.
“x” is a rational number.
“n” is an integer.
Now a rational number is simply a number which can be represented in the form i1/i2 where both “i1” and “i2” are integers. So we have:
y = i1/i2 * n
If we reduce “x” (which equals i1/i2) to its simplest form then the number you’re after (“smallest integer n that I can multiply the rational number x by so that y also becomes an integer”) is simply “i2”. To reduce “x” to its simplest form simply divide “i1” and “i2” by the greatest common divisor of “i1” and “i2”.
Here’s a function to find the greatest common divisor of two integers:
int gcd(int a, int b)
{
for ( ;; )
{
if (a==0)
{
return (b<0) ? -b : b;
}
b %= a;
if (b==0)
{
return (a<0) ? -a : a;
}
a %= b;
}
}
With this function you can find the answer you’re after like this:
n = i2/gcd(i1, i2)
This information may be of some help. Still you have to be able to get “i1” and “i2” from “x”.
Steve
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