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would this be able to work if the
user were to enter lets say 105,789
then i would need to display thousand place: 105
hundreds place is: 7
and so on
??
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or better yet, use .net: Textbox1.Text.SubString(i, 1) where i is the zero based index number of the position you want.
My advice is free, and you may get what you paid for.
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So i could use a For loop, correct?
thanks
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okay so this is the for loop i made but i know its wrong and it doesnt work all the time
I was just trying to see if it would at least display my tens place b4 i move on to work with the other values
For i = 0 To TextBox1.Text.Length - 1
tens = i
Label10.Text = tens
Next i
the textbox would be where the user would enter in the number
tens is a integer variable i created
and the label10.text is where i am displaying the tens value
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i also tried this for loop:
For index As Integer = TextBox1.Text.Length - 1 To 0 Step -1
MessageBox.Show(TextBox1.Text(index))
Next
i am just using the messagebox to get each individual character and show me that it is working.
i am really supposed to be sending it to separate textboxes.
but i dont know or understand how to send the first indexed item to the first textbox to be displayed, and then continue to
send out the other separated characters to the other textboxes.
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The question you first need to ask yourself is, how large a number can the user possibly enter? In other words, you will first have to determine how many positions you will have to report on (singles, tens, hundreds, thousands, tenthousands, hundredthousands, etc). In yet other words, how many textboxes will you need to put on your form?
So as Liqz suggested, it might be best to use Chars, and an array first, before using a loop.
Something like:
Dim PositionsArray() As Char = TextBox1.Text.ToCharArray
Now you can easily determine the number of characters:
Dim AmountOfPositions As Integer = PositionsArray.Length
Now you almost know how many positions you will have to handle. But what if we use your example: 105,749 ? This has a comma in the middle, which is also a position, but not a number.
Here you could use a For Each loop:
For Each c As Char In PositionsArray
'This will loop through the characters from left to right'
'Then play around with the possiblities of the Char type:'
If Not Char.IsDigit(c) Then
MsgBox("I found something other than a number (" & c.ToString & ")" & _
" at index: " & Array.IndexOf(PositionsArray, c))
End If
Next
Next you could look into the Case statement. like Steven suggested below.
My advice is free, and you may get what you paid for.
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First of all thank u so much for all the help
I tried using the case statement but when I tried to pass the myNumber.Units, Tens, and so on to display in a separate
textbox it wouldn't display anything.
Case 1
myNumber.Units = sEnteredNumber.SubString(idx, 1)
Textbox1.text = myNumber.Units
This is what i tried doing to display to the user what the ones, tens and so on were but it wouldn't display anything?
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First create a structure to hold the results
Structure NumberBreakDown
Dim Units as byte
Dim Tens as byte
Dim Hundreds as byte
Dim Thousands as integer
End Struture
Then
Dim myNumber as NumberBreakDown
Dim position as integer = 0
Dim sEnteredNumber as string = enteredNumberTextBox.Text.Trim
For idx as byte = sEnteredNumber.Length -1 to 0
position += 1
Select Case position
Case 1
myNumber.Units = sEnteredNumber.SubString(idx, 1)
Case 2
myNumber.Tens = sEnteredNumber.SubString(idx, 1)
Case 3
myNumber.Hundreds = sEnteredNumber.SubString(idx, 1)
Case Else
myNumber.Thousands = sEnteredNumber.SubString(0, sEnteredNumber.Length - Position +1)
End Select
Next
The above obviously does not handle commas and decimal places, but could easily be modified to.
Steve Jowett
-------------------------
Real programmers don't comment their code. If it was hard to write, it should be hard to read.
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I tried using this case statement but when I tried to pass the myNumber.Units, Tens, and so on to display in a separate
textbox it wouldn't display anything.
Case 1
myNumber.Units = sEnteredNumber.SubString(idx, 1)
Textbox1.text = myNumber.Units
This is what i tried doing to display to the user what the ones, tens and so on were but it wouldn't display anything?
Thank you for all the help
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I think there may be a small omission in Steven's code (and I apologise now if I am wrong, Steven!). But I think you need to tell the loop to count backwards, otherwise the loop is going to count up from the length of string - 1 to 0. Try adding 'Step -1' to the end of for statement.
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ok first of all THANK U STEVEN the code worked!
it was just missin that step -1 as u had stated
but the only thing is if i try to enter lets say
123456, just like that
the thousands place will only pick up 1, not 123
do i need to do a test if the number entered is
more then 4 digits long?
thank u everyone!
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Try changing the 'Case Else' statement to this:
Case Else
myNumber.Thousands = sEnteredNumber.SubString(0, Position - 3)
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Thanks it worked and i appreciate all da help!!!
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Could you post the entire code of the loop, and everything inside it, please?
My advice is free, and you may get what you paid for.
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well im at work right now and dont have the code on me
but it was just like stevens code
but the good thing is i got it to work
but the only thing im still trying to figure out
is when a user enters lets say: 12345
the thousands should show 12
but right now it onlh will display 1 only
and the hundreds and ones and tens do work properly
i was thinking maybe an if statement???
the only change i made to stevns case was added
step -1 to the end of the for loop
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Well, if you parse it into an actual integer, instead of using it as a string, it gets easier, using a combination of the "mod" (modulus) and "div" (division without remainder) operators...
123,456 mod 1000 = 456
456 div 100 = 4
So your "hundreds" place is (X mod 1000 div 100)
If you want to get more than just the one digit, like your other replies, skip the "mod" step and just run it through a div.
123,456 div 100 = 123
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You can use String.ToCharArray method. Then use TryParse to check if the character is an integer and then display it.
It's not necessary to be so stupid, either, but people manage it. - Christian Graus, 2009 AD
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Hello,
I am writting an aplication in VB.NET (not a website)
I would like to cache a datatable to save time when loading program, I will fill the datatable according to cache.
Here my code:
Imports System.Web.HttpRuntime
dtSynchronize = DirectCast(Cache("dtSynchronize"), DataTable)
If dtSynchronize Is Nothing Then
dtSynchronize = New DataTable
dtSynchronize.Columns.Add("EntryID", System.Type.GetType("System.String"))
dtSynchronize.Columns.Add("SyncData", System.Type.GetType("System.String"))
dtSynchronize.Columns.Add("StoreID", System.Type.GetType("System.String"))
End If
dtSynchronize.Rows.Clear()
dtSynchronize.Rows.Add("1", "2", "3")
Cache.Insert("dtSynchronize", dtSynchronize)
It works fine but when I am closing the application and opening it again, I expect that after the first line of code the dtSynchronize will not be Nothing but it is.
The cache is not saved.
Thank you
Shay Noy
modified on Tuesday, September 8, 2009 5:41 AM
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I found other solution by storing the datatble in a file and it works fine. Although, if someone has solution for storing it in a cache, please advise
Thank you
Shay Noy
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As a cache is only an area of memory it will disappear when your application closes unless you save it to disk or a database
Bob
Ashfield Consultants Ltd
Proud to be a 2009 Code Project MVP
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Thank you, I understood it later, I though it is the same cache like in ASP.net.
Shay Noy
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Hi, I am fairly a newbie to vb.net and am developing an inventory control windows application for a client.
I am creating a search form for my application. This search form searches the categorys table and returns the results in a datagrid view. The search bit of it is working, however what i want it to do next is not working!
I have a button on the Search form called "Return Data". Once the search results have been displayed in the datagrid view, the user will then select/highlight the row that they need. They will then click on the "Return Data" button and this button should then return the selected row in the datagrid view and display it in another datagrid view on another form.
I am just finding it extremely difficicult to getting this sorted. I have not got anywhere with it. Any sample code would be most appreciated.
Thanks
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ShabRaza wrote: Hi, I am fairly a newbie to vb.net and am developing an inventory control windows application for a client.
I pity the person who uses an inventory system written by a newbie. The world is insane.
ShabRaza wrote: Once the search results have been displayed in the datagrid view, the user will then select/highlight the row that they need. They will then click on the "Return Data" button and this button should then return the selected row in the datagrid view and display it in another datagrid view on another form.
The can select more than one row ? This Ui sounds odd, but you can iterate over your rows and check which have the selected property set to true.
Christian Graus
Driven to the arms of OSX by Vista.
Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.
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I pity immature people like you who make assumptions about others on a flip of a coin.
I wanted advice on helping me resolve a problem, not having someone make a dig at me. In the end you werent much useful and next time keep your opinions to yourself!
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