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U have to download the Ajax tool kit and msi setup file.
Download the <b>ASPAJAXExtSetup.msi</b> file from the below site to support Ajax in Asp.Net.
http://www.microsoft.com/downloads/details.aspx?FamilyID=ca9d90fa-e8c9-42e3-aa19-08e2c027f5d6&displaylang=en[^]
Download the Ajax control toolkit from the below site.
http://www.codeplex.com/AjaxControlToolkit/Release/ProjectReleases.aspx?ReleaseId=16488[^]
In the above page, at the top right corner u can see the topic Releases in a box. Click the link 20229. It redirects to another page. Select AjaxControltoolkit.zip under the topic Downloads&Files.
Run the msi file.
Follow these steps to add the ajax control toolkit to ur application:
1. Create a folder AJAX Control Toolkit at path C:\Program Files\Microsoft ASP.NET\ASP.NET 2.0 AJAX Extensions or the drive where you have installed the Windows on PC.
2. Then extract the files of downloaded Control Toolkit .zip inside new created folder.
3. You will get the following folders and files from the extracted items:
o AjaxControlExtender
o AjaxControlToolkit
o Binaries
o SampleWebSite
o TemplateVSI
o ToolkitTests
o AjaxControlToolkit.sln [Visual Studio Solution file]
4. Double click on AjaxControlToolkit.sln solution file to open it in Visual Studio 2005. It will show a security warning with two project load options:
o Load project for browsing
o Load project normally
5. Select load project normally and click ok.
6. After loading the solution it will display AJAXControlToolkit, SampleWebSite, ToolKitTests, TemplateVSI in the solution explorer.
Right click on TemplateVSI and click build. After successful compile and build go to the path X: or C:\Program Files\Microsoft ASP.NET\ASP.NET 2.0 AJAX Extensions\AJAX Control Toolkit\TemplateVSI\bin
At this path you will get the fresh build of AjaxControlExtender.vsi
7. Next Right click on SampleWebSite in the solution explorer and Build Web Site to get the fresh copy of AjaxControlToolkit.dll.
You will get the fresh AjaxControlToolkit.dll at :
X: or C:\Program Files\Microsoft ASP.NET\ASP.NET 2.0 AJAX Extensions\AJAX Control Toolkit\SampleWebSite\Bin
Note: You can see all the Control Toolkit components included in this framework by right clicking on above SampleWebSite in solution explorer --> select view in browser. It will show the sample web site showing the demo of all AJAX control toolkit components.
8. Now you are ready to add the Control Toolkit in your Visual Studio 2005.
First of all go to TemplateVSI bin folder discussed in step 6 and run AjaxControlExtender.vsi. This installer will install the ASP.Net web template that will enable you to create AJAX Control Toolkit Web Site.
9. After installing AjaxControlExtender.vsi, open the Visual Studio 2005 and go for New Web Site, there you will see a new My Template item as AJAX Control Toolkit Web Site, select it and create a new website.
How to include AJAX Control ToolKit Components in Toolbox
It’s also simple to add Toolkit on Visual Studio Toolbox. In the above new AJAX Control Toolkit Web Site, move your mouse on Controls Toolbox at right side and create a new Tab with name AJAX Toolkit. Then right click under the AJAX Toolkit tab and select choose items, this will open Choose Toolbox Items dialog box. Click on browse button at bottom and select the AJAXControlToolkit.dll file at this path: X: or C:\Program Files\Microsoft ASP.NET\ASP.NET 2.0 AJAX Extensions\AJAX Control Toolkit\SampleWebSite\Bin
It will populate the AJAX controls into the AJAX Toolkit tab.
When creating a new website select AjaxEnabledWebSite from the template side in VS 2005.
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how to verify and validate password that user have entered with the password in our database..
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I am sorry but I might not be understanding the difficulty here. Wouldn't you query the database, with the supplied UserName and Password, on the table which stores the user information and verify if a record exists ?
Select Count(*) from YourUserInfoTable where YourUsernameColumn = CurrentSuppliedUsername and YourPasswordColumn = CurrentSuppliedPassword
Or
Select * from YourUserInfoTable where YourUsernameColumn = CurrentSuppliedUsername and YourPasswordColumn = CurrentSuppliedPassowrd
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Let me guess - first day at work, and you therefore do not know anything about programming ? I suggest you buy a book on ASP.NET and one on SQL and you read them.
Christian Graus
Driven to the arms of OSX by Vista.
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Hey guys,
this is probably a stupid question... I'm not very active in web dev so please just bare with me
Here are two screen shots of web pages that have been zoomed out Code Project Zoomed Out[^] and Facebook Zoomed Out[^]
The site I'm developing is like CodeProject zoomed out, how do i get it to look like an "actual page" as per the facebook zoomed out screen shot?
I'd google it, but what the hell would i search for?? 
Harvey Saayman - South Africa
Software Developer
.Net, C#, SQL
you.suck = (you.Passion != Programming & you.Occupation == jobTitles.Programmer)
1000100 1101111 1100101 1110011 100000 1110100 1101000 1101001 1110011 100000 1101101 1100101 1100001 1101110 100000 1101001 1101101 100000 1100001 100000 1100111 1100101 1100101 1101011 111111
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I would say that the zooming is more of a browser feature than the web page. The browser will take the page as it looks and zoom out, but for the webpage the window size remains the same. At least that's the way I see it in IE 7.
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The question isn't really about the zooming out, the effect I need it just more apparent that way.
Did you look at the screen shots? See the difference?
Harvey Saayman - South Africa
Software Developer
.Net, C#, SQL
you.suck = (you.Passion != Programming & you.Occupation == jobTitles.Programmer)
1000100 1101111 1100101 1110011 100000 1110100 1101000 1101001 1110011 100000 1101101 1100101 1100001 1101110 100000 1101001 1101101 100000 1100001 100000 1100111 1100101 1100101 1101011 111111
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harvey isn't that dependent on how you write the containing div for the page?
if you make it 100% width it scales and stretches ... if you fix the width and center it you would get the 2nd example afaik
"mostly watching the human race is like watching dogs watch tv ... they see the pictures move but the meaning escapes them"
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Harvey Saayman wrote: Did you look at the screen shots? See the difference?
Yes, CP looks smaller and stretches all over the window, while Facebook just looks smaller proportionally.
I tried zooming CP (with IE 7) to 75% and I get somehting smilar to your FB screenshot: it doesn't fill the entire window. That's why I say that it might be the browser more than the HTML you use.
[EDIT: This[^] is how I see CP at 50%]
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Hi all,
I am trying to type text in text box using following statement
ie.TextField(Find.ByName("USER")).Value="username";
when i tried this iam getting an exception--
"Could not find INPUT (text password textarea hidden) or TEXTAREA element tag matching criteria"
also i tried "ie.TextField(Find.ByName("USER")).Typetext" but in vain
How to resolve this problem ...please help me out
Thanx in advance
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What are you trying to achieve?
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Iam trying to login to a secure server...........
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Hi,
I am completely new to generating reports in SSRS in ASP.NET and C#.I have generated a report successfully. Now what I need is I dont dont want to show any columns or fields in the report when there is no data.
The requirement is very urgent. So I request a quick reply from any one who knows solution to this.
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select column and go to properties, then select visibility and put in Hidden
=IIF(Fields!NameOfColumn.Value=0,True, False)
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There is no "COLUMN" visibility property. There is a row visibitly property and there is a cell specific visibility property. Not for COLUMN!
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If you select column, go to properties, select visibility property and underneath Visibility Select Hidden and select Expression from drop down list box.
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Hi,
I have developed a MIS based project using framework 2.0 & sqlserver 2000. I want to send MIS report on mail through sqlserver using schedular, without open my website. Is there any procedure to solve this? or any other solutions?
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you can do this by window service also
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Hi
I want to generate the menu from database.
pages and thier content are come from the database.
i mean that pages and thier content are come from database and
generate menu dynamic.
Keyur Satyadev
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Doing this, will require code...
I would imagine you'd use a repeater to build a menu from a data source, and if the pages are dynamic, build a single page that takes a query string and requests a page from the database. Beyond that, it's impossible to help you based on the (lack of) information you provide here.
Christian Graus
Driven to the arms of OSX by Vista.
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give your menu datasource property to datatable you are taking from database
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Sessions DO NOT end when a user closes their browser. There is no communication with the server when a browser is closed so there is no way the server can know to end the session. The same is true when you leave the site for another. Again no communication takes place between your browser and the site you're leaving so the server never knows you've left.
Basically the only solution I know of is to set up a client-side event to call a server-side script to abandon the session when the user leaves.
Anyone knows how to write a javascript to end a session when the browser is being closed?
Any help will be appreciated!
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You fire off an AJAX message on the event that fires when the form closes. Then you accept that even this is not foolproof, so you still write timeout code rather than assume the user stays logged in until that message arrives.
Christian Graus
Driven to the arms of OSX by Vista.
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hi,
I need to write a background working app which can be installed on server (shared Server)
So here some one suggested to write a windows service for this .
I have written the coding in the start function of Service1.cs
I have written
protected override void OnStart(string[] args)<br />
{<br />
<br />
ThreadStart Thstart = new ThreadStart(startfunction);<br />
<br />
mytheread = new Thread(Thstart);<br />
<br />
mytheread.Start();<br />
<br />
<br />
}
but when i debug it its not getting executed .. i have the start function definition ..
I have scour the web but was not able to find a proper solution.
Please help me in this
thanks
If You win You need not Explain............
But If You Loose You Should not be there to Explain......
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