fetch the records based on the condition

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SQL-Server-2008R2

Hi,

I have a table which consists of 6 fields with one field name as status.
table consists of 10 rows.
Status field consists of data from 1 to 10.

Here I need to fetch the data based(order by) on the status value, but value may be varied depending on the requirement.

For example, record with status value 6 need to be fetched as a first row of the table

I tried in google but couldn't get it.

Please help me on this.

thanks in advance.

Posted 3-Mar-15 22:54pm

sri4dotnet

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King Fisher 4-Mar-15 5:09am

show your table structure and expected Resultset .

2 solutions

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Peter Leow · Answer 1 · 2015-03-03T23:27:00

Solution 1

Try this:

SQL

select * from tablename where status = 6
union
select * from tablename where status <> 6

Posted 3-Mar-15 23:27pm

Peter Leow

Comments

sri4dotnet 4-Mar-15 5:39am

Thanks for your reply.
I have tried this but may be a case 6 cannot be in the table then the row will be null

Peter Leow 4-Mar-15 6:02am

I do not get you. If the status of 6 does not exist, then there is no question of it being in the first row in the first place.

**Orcun Iyigun** · Answer 2 · 2015-03-04T01:08:00

You can use a custom sort by clause in your query.

For example

SQL

SELECT Column1, Column2
                FROM   dbo.Country
                ORDER BY CASE WHEN Status = 6 THEN 1
                              WHEN Status = 5 THEN 2
                              ELSE Status END ASC

For more detailed information please check this link[^].

Good luck,
OI