How to Subtract a given date

Question

0.00/5 (No votes)

See more:

Hi Guys,

Can you help me in how to Subtract a given date from an given integer with a format of a "MM/DD/YYYY"?

Please help me ....

Thanks in Advance...

Posted 12-Jun-10 1:46am

jleonorlane

Updated 12-Jun-10 6:20am

Abhinav S

v2

Add a Solution

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sandeep Mewara · Answer 1 · 2010-06-12T02:07:00

jleonorlane wrote:
Subtract a given date from an given integer

How come a date can be substracted from an integer? Both are totally different datatypes.

Looks like you want to substract integer number of days from a given date, if so, do something like:
myDate.AddDays(-1*numberToDeduct);

Converting date in a particular format, do like:
(Convert.ToDateTime(myDate)).ToString("MM/dd/yyyy");

Anshul R · Answer 2 · 2010-06-12T18:21:00

Solution 3

If the integer represents days,

VB

Dim x As New Date
Dim i As Integer = 0
Dim xdays = TimeSpan.FromDays(x.TimeOfDay.Days)
Dim idays = TimeSpan.FromDays(i)
Dim diff = (xdays - idays)

Posted 12-Jun-10 18:21pm

Anshul R

Abhinav S · Answer 3 · 2010-06-12T06:19:00

Solution 2

You might want to have a look at this and this.

Posted 12-Jun-10 6:19am