how to evalueate variables inside strings in c#

Question

5.00/5 (1 vote)

See more:

Hello,
Is it possible in c#.............

string a = "10";
string b = 20;
string c = 40;

k="a*b+c";
m="a+b+c";
n="a*b*c"
string output = evaluate(k) // output =240

string output = evaluate(m) // output =70

string output = evaluate(n) // output =800

if yes please help me how do this in c#...
variable are declared at runtime
and formula of k,m,n is sroted in database. and fetch at runtime.
=============================

actually the real scenario is as :- i have several variables stored in table.
table1:fieldmaster
field_name | field_type | field_length
ab varchar 20
bc varchar 20
ca varchar 20
and i fetch all field_name in a table.
and took a dictionary and add field_name as dictionary key.
and in for loop assign values to each key
----
now in other table i have some formula which evaluate fields.
table2 : formulamast
field_name | formula
ca | ab+(bc*bc)
now i have to evaluate values of ca according to formula which is in formula table.

Posted 28-Jan-15 0:24am

Member 8083455

Updated 28-Jan-15 1:53am

v3

Add a Solution

Comments

Member 8083455 28-Jan-15 7:55am

thanks for support.. but it solve if i have integer, but i have string.
now i have updated my question to clear it.

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard Deeming · Answer 1 · 2015-01-28T02:16:00

Solution 2

This might help:
Flee - Fast Lightweight Expression Evaluator[^]

Posted 28-Jan-15 2:16am

Richard Deeming

Atish K. Singh · Answer 2 · 2015-01-28T00:43:00

Solution 1

Please try below code

C#

try
{
    string Expr = "(1+1+1)*1";
    var result = new DataTable().Compute(Expr, null);

}
catch { }

Hope this will solve your purpose.

Posted 28-Jan-15 0:43am

Atish K. Singh

Updated 28-Jan-15 0:44am

v2