How to list files in the GUID pattern form

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due to some code many files of the form
"acd5604f-5bbd-4e94-9b40-ea0247cdb4ad"
have been created in some of the clients' folders. These files are created using some GUID() function and they have no extension.
I needed to remove them, what is the pattern that helps getting them in the easiest way.

Posted 15-Jun-14 22:58pm

Tarek Elqusi

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Prasad Avunoori 16-Jun-14 5:04am

//Generate New GUID
Guid objGuid = Guid.NewGuid();
//Take invalid guid format
string strGUID = "aaa-a-a-a-a";

Guid newGuid;

if (Guid.TryParse(objGuid.ToString(), out newGuid) == true)
{
Response.Write(string.Format("<br/>{0} is Valid GUID.", objGuid.ToString()));
}
else
{
Response.Write(string.Format("<br/>{0} is InValid GUID.", objGuid.ToString()));
}

Guid newTmpGuid;

if (Guid.TryParse(strGUID, out newTmpGuid) == true)
{
Response.Write(string.Format("<br/>{0} is Valid GUID.", strGUID));
}
else
{
Response.Write(string.Format("<br/>{0} is InValid GUID.", strGUID));
}

Prasad Avunoori 16-Jun-14 5:05am

Customize the above code according to your need.

2 solutions

Solution 2

The pattern is:
- 8 hexadecimal digits
- dash
- 4 hexadecimal digits
- dash
- 4 hexadecimal digits
- dash
- 4 hexadecimal digits
- dash
- 12 hexadecimal digits

A regular expression could catch it easily:

C#

Regex r = nex Regex(@"^[0-9a-zA-Z]{8}-[0-9a-zA-Z]{4}-[0-9a-zA-Z]{4}-[0-9a-zA-Z]{4}-[0-9a-zA-Z]{12}$"

string fileName;
foreach (FileInfo fi in dir.GetFiles()) {
   fileName = fi.FileName;
   if (r.IsMatch(fileName)) { // Here the file name is a GUID
      fi.Delete();
   }
}

Posted 15-Jun-14 23:11pm

phil.o

Updated 15-Jun-14 23:15pm

v2

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DamithSL · Accepted Answer · 2014-06-15T23:07:00

Solution 1

you can use Guid.TryParse Method[^]

C#

string filename = "acd5604f-5bbd-4e94-9b40-ea0247cdb4ad";
Guid guid;
if(Guid.TryParse(filename , out guid))
{
   //delete file 
}

Posted 15-Jun-14 23:07pm

DamithSL

Updated 15-Jun-14 23:08pm

v2