How Can I Update Datatable Using Linq Query

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Hello,

C#

String GrossPrem = "5000";
String OtherPrem = "100";
int i_id = 1;
DataTable Installment = SomeDataTable;

Installment.AsEnumerable().Where(x => x.Field<string>("PayNo").ToString().Equals(i_id.ToString())).FirstOrDefault<DataRow>
(t => t.Field<string>("GrossPrem") = GrossPrem,
                t.Field<string>("OtherPrem") = OtherPrem,
                t.Field<string>("DueDate") = "05/21/2014").AcceptChanges();

I am new to use linq query.

Here i want to update table data using linq
but i get error.

please help me to resolve.

Thanks In Advance

Posted 21-May-14 3:48am

PKriyshnA

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joshrduncan2012 21-May-14 10:16am

It would help if you told us where the error was pointing to and what the text of the error is. We can't read your mind.

2 solutions

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Vedat Ozan Oner · Answer 1 · 2014-05-21T09:53:00

possibly you get a compile error because of FirstOrDefault extension method. It has two forms:

either:

XML

public static TSource FirstOrDefault<TSource>(
    this IEnumerable<TSource> source
)

or

XML

public static TSource FirstOrDefault<TSource>(
    this IEnumerable<TSource> source,
    Func<TSource, bool> predicate
)

First version, simply selects a value from a given IEnumerable. The second one needs a selector function. Your usage doesn't match any of these two. Therefore, a compile error.

Since you don't know how to use it I advice you to check out some samples on msdn and other sites.

documentation is here:
FirstOrDefault[^]

another advice is to use typed datasets and tables. use the designer of the IDE to create your data structures.
see here: create dataset[^]

and a good start point for linq: LINQ[^]

If you follow instructions on these pages, you can have deeper understanding of those concepts and tools.

have a good day.

sankaruma · Answer 2 · 2014-11-14T03:17:00

Solution 2

SQL

dtNewLCM.AsEnumerable().Where(row => row.Field<string>("leafClass")=="0")
    .Select(b => b["leafClass"] = "MyValue1.")
    .ToList();

Posted 14-Nov-14 3:17am

sankaruma