Get Exact calculated total Hours and minutes in sql server

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Hi! Good day. Im using ms sql server 2005 express and heres my table structure:

SQL

 USER |        Log_Date        |       Log_In_Time     |      Log_Out_Time     |
--------------------------------------------------------------------------------
 xxx  | 2013-10-02 23:00:31.623|2013-10-02 23:07:31.623|2013-10-03 01:08:31.623|

NOTE:

LOG_OUT_TIME is in other day which is October 3, 1:08 AM , LOG_IN_TIME is October 2, 11:00 PM

Now I want to add column: TOTAL

and it look like this:

SQL

|TOTAL|
-------
|2.08 |

Can anybody know the way?

Thank you in advance!

Posted 22-Oct-13 22:55pm

Uknownymous

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Amol_B · Answer 1 · 2013-10-22T23:19:00

Solution 2

You can use DATEDIFF as

SQL

SELECT DATEDIFF(HOUR,Log_In_Time,Log_OUT_Time)

or

SQL

SELECT DATEDIFF(mi,Log_In_Time,Log_OUT_Time)/60;

Plese refer
http://technet.microsoft.com/en-us/library/ms189794%28v=sql.90%29.aspx[^]

Posted 22-Oct-13 23:19pm

Amol_B

Updated 22-Oct-13 23:21pm

v2

OriginalGriff · Answer 2 · 2013-10-22T23:18:00

Solution 1

Try:

SQL

SELECT CAST(DATEDIFF(mi, Log_In_time, Log_Out_Time) AS FLOAT)/60 AS Total FROM MYTable

But do note - you sample doesn't generate the number you show!

Posted 22-Oct-13 23:18pm

OriginalGriff

VeeraAnnapureddy · Answer 3 · 2013-10-22T23:27:00

Solution 3

SQL

Declare @Time int,@LoginTime datetime = '2013-10-02 23:00:00',@LogoutTime datetime = '2013-10-03 01:08:00'

Set @Time = DATEDIFF(Minute,@LoginTime,@LogoutTime)

SELECT CAST( @Time/60 AS VARCHAR(5))+ ' Hrs' + ':'+ RIGHT('0' + CAST( @Time%60 AS VARCHAR(2)), 2)+' Min' AS 'WorkingTime'

Posted 22-Oct-13 23:27pm

VeeraAnnapureddy

Padam Agrawal · Answer 4 · 2013-10-23T00:41:00

Solution 4

Try these, hope you will get ans,

SQL

select DATEDIFF(hh,getdate(),getdate()+1) --For hours
select DATEDIFF(mi,getdate(),getdate()+1) --for mins

Posted 23-Oct-13 0:41am

Padam Agrawal

Updated 23-Oct-13 0:42am

v2