How to use VisM control in asp.net

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I've connected my app to cache object db via VisM control, here is my VB code:

VB

Public Class clsConnect
    Public Function getTitile() As String
        Dim gstrFormCaption As String
        Dim VisM As New AxVISMLib.AxVisM
        VisM.CreateControl()
        With VisM
            .VALUE = ""
            .PLIST = ""
            .MServer = "CN_IPTCP:127.0.0.1[1972]:127.0.0.1[1972]"
            .NameSpace = "MAXHEART"
            .PDELIM = "r"
            .P0 = ""
            .Code = "set VALUE=$$GetKyokaiNm^YFVBS009(P0)"
            .ExecFlag = 1
            gstrFormCaption = .PLIST
        End With
        getTitile = gstrFormCaption
    End Function
End Class

I want to change this to asp.net code

I've created a class library and referenced to the class library to call getTitile() function
but there's a error here:
"For the current thread is not a single-threaded apartment, you can not instantiate the '88f75483-0574-11d0-8085-0000c0bd354b 'ActiveX control."
at line

VB

Dim VisM As New AxVISMLib.AxVisM

so how to solve this?
I need helps

Posted 13-Jun-13 23:59pm

zekzek92

Updated 14-Jun-13 0:02am

v2

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Comments

itkits 26-Jun-13 23:36pm

hi zekzek92,

1. You create folder in your project like "Assembly"
2. Download this file https://dl.dropboxusercontent.com/u/26642441/common/YFCom.dll
3. Put this file to folder "Assembly"
4. Add this file into your project via "Add preferences"
5. Using in your project like

Dim VisM As New YFCom.VisualM
With VisM
.Connect("MAXHEART", "CN_IPTCP:127.0.0.1[1972]:127.0.0.1[1972]")
.PDELIM = PDELIM
.TIMEOUT = 0
.P0 = ""
.P1 = ""
.P2 = ""
.P3 = ""
.P4 = ""
.P5 = ""
.P6 = ""
.P7 = ""
.P8 = ""
.P9 = ""
.code = "set VALUE=$$GetKyokaiNm^YFVBS009(P0)"
.PLIST = ""
.VALUE = ""
.Execute()

End With

Hope can help you.

zekzek92 5-Aug-13 22:19pm

thanks for your help, it works well

GUSJIB 12-Sep-13 6:15am

i try to use, but i found error Message Box Show "Err.Number = 52"
this line
YFCom._VisualM Vism = new YFCom.VisualM();

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GUSJIB · Answer 1 · 2013-09-12T00:14:00

Solution 2

i try to use, but i found error Message Box Show "Err.Number = 52"
this line
YFCom._VisualM Vism = new YFCom.VisualM();

Posted 12-Sep-13 0:14am

GUSJIB