Need help with the sql query

Question

0.00/5 (No votes)

See more:

I have a table with two columns statecode and state having values as-
Statecode state
1 DLI
2 MH
3 UP
2 DLI

In my output i need only those rows that do not have duplicate values in any of the column, I.e., O/p should be like

Statecode State
2 MH
3 UP

Posted 20-Aug-13 6:34am

Member 10221062

Add a Solution

2 solutions

Solution 1

SELECT DISTINCT statecode, state FROM 'table'

Posted 20-Aug-13 6:42am

Richard C Bishop

Comments

Member 10221062 20-Aug-13 12:44pm

I tried that too, but it will give me my output as
Statecode state
1 DLI
2 MH
3 UP

whereas i dont want 1 DLI in my output.. :(

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

fixthebugg · Accepted Answer · 2013-08-20T07:23:00

Solution 2

get duplicates using

SQL

select state from statetable ,count(*)
group by state 
having count(*) > 1

then you can get rid of them using

SQL

select statecode, state from statetable 
where state not in ()

Posted 20-Aug-13 7:23am

fixthebugg

Updated 20-Aug-13 9:27am

v4

Comments

Member 10221062 20-Aug-13 13:27pm

Thnks for the help.. i will try this, hopefully this will work.. thnks once again.. :)