show form dynamically, with string value

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normaly this is how i open a form, with 2 parameter

C#

FmCalculate cc = new FmCalculate("456", "123");
FmCalculate.ShowDialog();

now how can i open the form by using the string value
for example:

C#

String strFormName = "FmCalculate";

i tried below example, but it said the value is null, and how to include the "456" and "123" parameter?

C#

Form form = (Form)Activator.CreateInstance(Type.GetType("FmCalculate"));
form.ShowDialog();

Posted 4-Aug-13 2:06am

melvintcs

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Moreno Airoldi · Accepted Answer · 2013-08-04T04:04:00

You should provide a fully qualified name type, including your namespace. That's why you're getting a null. For example:

C#

Form form = (Form)Activator.CreateInstance(Type.GetType("MyNameSpaceName.FmCalculate"));

And you should be able to pass any constructor parameters directly like:

C#

Form form = (Form)Activator.CreateInstance(Type.GetType("MyNameSpaceName.FmCalculate","456", "123"));

Also, if you're using a .NET version above 2 (if I remember correctly) you should be able to use the generic function call Activator.CreateInstance<t>()</t>:

C#

FmCalculate form = (FmCalculate)Activator.CreateInstance("456", "123"));

I'm going by memory here, so there may be some small inaccuracy. :-)
Please check the MSDN page on Activator.CreateInstance() for more details.