How to get the license key?

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How to get the license key in windows application. And i need 2PHXF-9PBDW-D3WWY-CPDKD-XG87V this format. Please help me....
i have tried this code

C#

private void btn_License_Click(object sender, EventArgs e)
       {
           Random ran = new Random();
           textBox1.Text = "" + ran.Next(0, 9) + ran.Next(0,9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + "_" + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + "_" + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9) + ran.Next(0, 9);
       }

Posted 8-Jul-13 18:46pm

Rajan from Thiruvananthapuram

Updated 8-Jul-13 18:48pm

v2

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Sushil Mate 9-Jul-13 0:49am

Do you know how to create installer? This is same question you have posted here.

3 solutions

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Rajan from Thiruvananthapuram · Accepted Answer · 2013-07-08T21:13:00

My Soltion is:

private static Random rd = new Random((int)DateTime.Now.Ticks);

C#

private void btn_License_Click(object sender, EventArgs e)
       {

           string str1 = GeneratePassword(5, 0);
           string str2 = GeneratePassword(5, 0);
           string str3 = GeneratePassword(5, 0);
           string str4 = GeneratePassword(5, 0);
           string str5 = GeneratePassword(5, 0);
           textBox1.Text = str1 + "-" + str2 + "-" + str3 + "-" + str4 + "-" + str5;

C#

}

       public static string GeneratePassword(int Lenght, int NonAlphaNumericChars)
       {

           string allowedChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
           string allowedNonAlphaNum = "!@#$%^&*()_-+=[{]};:<>|./?";
           //Random rd= new Random((int)DateTime.Now.Ticks);

           if (NonAlphaNumericChars > Lenght || Lenght <= 0 || NonAlphaNumericChars < 0)
               throw new ArgumentOutOfRangeException();

           char[] pass = new char[Lenght];
           int[] pos = new int[Lenght];
           int i = 0, j = 0, temp = 0;
           bool flag = false;

           //Random the position values of the pos array for the string Pass
           while (i < Lenght - 1)
           {
               j = 0;
               flag = false;
               temp = rd.Next(0, Lenght);

               for (j = 0; j < Lenght; j++)
                   if (temp == pos[j])
                   {
                       flag = true;
                       j = Lenght;
                   }

               if (!flag)
               {
                   pos[i] = temp;
                   i++;
               }
           }

           //Random the AlphaNumericChars
           for (i = 0; i < Lenght - NonAlphaNumericChars; i++)
               pass[i] = allowedChars[rd.Next(0, allowedChars.Length)];

           //Random the NonAlphaNumericChars
           for (i = Lenght - NonAlphaNumericChars; i < Lenght; i++)
               pass[i] = allowedNonAlphaNum[rd.Next(0, allowedNonAlphaNum.Length)];

           //Set the sorted array values by the pos array for the rigth posistion
           char[] sorted = new char[Lenght];
           for (i = 0; i < Lenght; i++)
               sorted[i] = pass[pos[i]];

           string Pass = new String(sorted);

           return Pass;
       }

Result is:Y4CDQ-GAIW5-VIWE1-0EFN6-C5Z7H

Rajan Maheshwari · Accepted Answer · 2013-07-08T21:20:00

Here is the C# code.Just click on button and you will get different license keys

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {
        Random random = new Random();
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            string s1 = RandomString();
            string s2 = RandomString();
            string s3 = RandomString();
            string s4 = RandomString();
            string s5 = RandomString();
            textBox1.Text = s1+" - "+s2+" - "+s3+" - "+s4+" - "+s5;
        }

      public string RandomString()
        {
            string input = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
            StringBuilder builder = new StringBuilder();
            char ch;
            for (int i = 0; i < 5; i++)
            {
                ch = input[random.Next(0, input.Length)];
                builder.Append(ch);
            }
            return builder.ToString();
        }
    }
}

Check out and let me know if it helped

Rajan Maheshwari · Accepted Answer · 2013-07-08T18:50:00

Solution 1

just make 5 labels.
Make a char randomize function.You can find the randomize function of characters of 5 digits on net
At last concatenate the string of all the labels and store in a database and then if you wish you can print in a label or a textbox and you are done..

Posted 8-Jul-13 18:50pm

Rajan Maheshwari

How to get the license key?

3 solutions

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