__int64 to LARGE_INTEGER

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C++

__int64 FileSizeDistance = 2711617536;

LARGE_INTEGER liSize;

liSize.LowPart = (int)(FileSizeDistance & 0xFFFFFFFF);
liSize.HighPart = (int)(FileSizeDistance >> 32);

_tprintf("LowPart:%d, HighPart:%d\n", liSize.LowPart, liSize.HighPart);

return 0;

The result is :

LowPart: -1583349760, HighPart: 0

What is the right way?

Posted 7-Jul-13 20:32pm

Member 8911328

Updated 7-Jul-13 20:49pm

AlphaDeltaTheta

v2

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3 solutions

Solution 1

I see that your compiler has support for 64bit signed integers. So you need to use the QuadPart member to store the value.

C++

LARGE_INTEGER liSize;
liSize.QuadPart = FileSizeDistance;

See MSDN[^] for details.

Good Luck!

Posted 7-Jul-13 20:49pm

AlphaDeltaTheta

Solution 3

Your value has been correctly loaded into liSize, although you could have done it an easier way, as solution 1 demonstrates. The problem in your code is the print out part. You used %d for the low order part LowPart, which is however an unsigned int. If you use %u instead you will receive the correct result. And it is correct that the high part is 0.

Posted 7-Jul-13 20:58pm

nv3

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Jochen Arndt · Accepted Answer · 2013-07-07T20:54:00

The simplest would be

C++

liSize.QuadPart = FileSizeDistance;

Your assignment is not wrong, but the castings should be according to the desitination type (DWORD for LowPart and LONG for HighPart). Even your print output is correct. To get the expected output, just print the low part as unsigned:

_tprintf("LowPart:%u, HighPart:%d\n", liSize.LowPart, liSize.HighPart);