Changing COUT behaviour when dealing with "byte" type defined by myself as typedef char.

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Is there any way to alter the behavior shown in the console when displaying a char?
I mean, I created my type called byte, which comes from char but I want byte to show a number, not a symbol from the ASCII table.

Suggestions?

Thanks.

Posted 25-May-13 21:16pm

unscathed18

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Santhosh G_ · Accepted Answer · 2013-05-25T22:29:00

Solution 1

Please implement << operator function for byte.

C++

class Byte
{

  friend ostream& operator<<(ostream& s, Byte b)
  {
    s<<( b.m_a ); // Here display whatever you want with your member. Prepare integer version display or other formatted string, and put to the output stream
    return s;
  }
};
// From main function
main()
{
byte b(20);
cout<<b;
}

Please refer following link to know more details about operator overloading.
http://www.cprogramming.com/tutorial/operator_overloading.html[^]

Posted 25-May-13 22:29pm

Santhosh G_

Updated 25-May-13 22:34pm

v3

Comments

unscathed18 31-May-13 6:45am

OK, this works well, but by the simple type wrapping I am just hiding away the conversions in between. Isn't there anyway to show a "char" as a number instead of a ASCII display? I guess it should depend on the OS console. The solution you provided above needs to make a prior conversion whether to a non-char type or a string.