String Compare in Sql Server

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String Compare in Sql Server i have two string (str1 and str2).
For Example:-

SQL

str1=mithilesh kumar
str2=mzthilesh kumar
then outPut is
error at position= 2.


str1=mithilesh kumar
str2=mzthilesh kamar
then outPut is
error at position= 2, 12,

str1=mithilesh kumar
str2=mithilesh kumar
then outPut is
error at position= 0.

Posted 16-May-13 21:14pm

bhartimithilesh

Updated 16-May-13 21:23pm

gvprabu

v2

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Sant Osha 17-May-13 3:23am

question not clear, plz modify so that we an understand

gvprabu 17-May-13 3:24am

U need to compare str1,str2 in sql server right. give more information abt ur problem.

Zoltán Zörgő 17-May-13 4:29am

You want to find out at what position the strings differ? And you want the result as a string with comma separated values?

2 solutions

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Sant Osha · Answer 1 · 2013-05-16T21:33:00

Solution 1

this might help you

SQL

declare @str1 varchar(10)
declare @str2 varchar(10)
set @str1='mithilesh kumar'
set @str2='mzthilesh kumar'
select case when @str1=@str2 then 'Same' else 'Different' end

Posted 16-May-13 21:33pm

Sant Osha

Updated 16-May-13 21:34pm

v2

__TR__ · Answer 2 · 2013-05-16T21:39:00

Here is a sample.

SQL

DECLARE @Str1 VARCHAR(100)
DECLARE @Str2 VARCHAR(100)
DECLARE @I INT
DECLARE @Result VARCHAR(100)

SET @Str1 = 'mithilesh kumar'
SET @Str2 = 'mzthilesh kumar'
SET @I = 1
SET @Result = 'Error At Position = '


IF PATINDEX(@Str1, @Str2) = 1
BEGIN
	-- Both strings are equal. 
	SET @Result = @Result + ' 0.'
END
ELSE
BEGIN
	-- Strings are not equal.
	WHILE @I <= LEN(@Str2)
	BEGIN

		
		IF (SUBSTRING(@Str1,@i,1) != SUBSTRING(@Str2,@i,1))
		BEGIN
			SET @Result = @Result + CAST(@I AS VARCHAR) + ', '
		END
		
		SET @I = @I + 1

	END
	--Remove the comma at the end and add a Period '.'
	SET @Result = SUBSTRING(@Result,1,LEN(@Result)-1) + '.'
END	



SELECT @Result AS [Output]

Hope this helps.