C++11 lambda as default param for template's functor type

I'm not sure it is possible with lambdas, it's looking rather like a polymorphic lambda. check here[^]. I just don't think lambdas were intended to be used in the context of template based generic programming.

The closest I have managed to get to implementing what you have above is this:

template <typename T>
T& func(T& val)
{
    val++; 
    return val;
}

template <typename T, T&(*Func)(T&) = func<T>>
class SomeClass
{
public:

    SomeClass() : val(0) {};
    void CallIt()
    {
        std::cout << "val before call = " << val << std::endl;
        Func(val);
        std::cout << "val after call = " << val << std::endl;
    }
private:
    T val;  
};

int main(int argc, char* argv[])
{
    SomeClass<int> instance;
    instance.CallIt();

	return 0;
}

But then that doesn't help with your original question wrt playing around with lambdas, and it is also probably just as simple to use a functor in my particular example.

I'd love to here if someone managed to do this, or by using std::function as a wrapper for a lambda.