Implementation of gets_s function,

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VS2012

I have this problem with the gets_s function. This is my code snippet:

C++

char *string;
	int n;
	printf("Enter the max length:\n");
	scanf_s("%d",&n);
	printf("Enter the string:\n");
	gets_s(string);
	printf("%s",string);

The Errors I've been facing is this:
error C2660:'gets_s':function does not take 1 arguments
IntelliSense: no instance of overloaded function "gets_s" matches the argument list argument types are: (char *)

However, if I statically allocate
char string[ARRAY];(with a macro defined for size as ARRAY) I havent been facing any problem. I want the end user to define its own size. Someone please help me out!

Posted 7-Mar-13 5:50am

Sanzie

Updated 7-Mar-13 6:00am

Sandeep Mewara

v2

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[no name] 7-Mar-13 12:04pm

http://msdn.microsoft.com/en-us/library/5b5x9wc7%28v=vs.80%29.aspx

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OriginalGriff · Answer 1 · 2013-03-07T06:03:00

gets_s does not take a single parameter - it takes two: http://en.cppreference.com/w/c/io/gets[^] You need to supply a size as well as a buffer.

However, since the code you show does not allocate any memory to the string parameter all you will do is pass in a null pointer and your application will immediately crash! :laugh:

Try using the malloc function to allocate some space - but don't forget to free it when you are finished with it!

Michael Haephrati · Answer 2 · 2013-03-07T06:15:00

gets() vs gets_s()

gets_s() is part of the new C11 standard and the replacement of the old gets(), but is safer. You can use gets() but you will then get a warning encouraging you to switch to gets_s(). As opposed to gets() that doesn't perform bounds checking, gets_s() restrict the length

What makes gets_s() safer?
gets_s() requires you to add another parameter which is the maximum size of the expected input to prevent access violation due to endless strings (without 'null' in their end),

H.Brydon · Answer 3 · 2013-03-08T04:46:00

The difference between gets() and gets_s() is that gets() writes characters out to an array that you provide and trusts that you have enough room, while gets_s() does a check for length before writing. For the following:

C++

char* array1 = new char[20];
gets_s(array1);  /* error */

char array2[20];
gets_s(array2);

The compiler can determine (at compile time) that array2 is of size 20, but can not do the same for array1. Whenever you pass a pointer to gets_s(), you also need to pass its length for the code to compile.

See the Microsoft documentation here[^].

Implementation of gets_s function,

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