How do I run the program code with an array 1 row and 0 column in C++?

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#include <iostream>
using namespace std;

int main()
{
// an array with 1 row and 0 column.
int arr[1][0] ={1};
int i, j;

cout<<"Printing a 2D Array:\n" ;

// output each array element's value
for(i=0;i<1;i++)
{
for(j=0;j<0;j++)
{
cout<<"\t"<<arr [i][j];
="" }
="" cout<<endl;
=""
="" return="" 0;
}

<b="">What I have tried:

main.cpp: In function ‘int main()’:
main.cpp:15:22: error: too many initializers for ‘int [1][0]’
15 | int arr[1][0] ={1};
| ^

It becomes like this, so that I don't know to solve it.

Posted 23-Nov-22 16:28pm

alia zulaika

Updated 23-Nov-22 23:47pm

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CPallini · Accepted Answer · 2022-11-23T22:24:00

Solution 2

A bidimensional array has (rows x columns) items.
Since, in your case, columns = 0, the array has 0 items. The compiler, as usual, is correct.

Posted 23-Nov-22 22:24pm

CPallini

longjmp · Accepted Answer · 2022-11-23T23:47:00

"1 row and 0 column", I think it doesn't have space to store any element, but

int arr[1][0] ={1};

tried to store an element to array, that's not correct,
if you need an array that every element is also an array, and it includes one element like this, you can code:

#include <vector>
#include <iostream>
using namespace std;
void test()
{
	vector< vector<int> > v(1);
	cout << "v.size ==" << v.size() << "; v[0].size == " << v[0].size() << endl;
}

or you can code:

int* arr[1]; //arr[1] is a pointer, and it can pointer to an int-array later
int arr1[] = { 1,2,3 };
arr[0] = arr1; // now arr[0][1] == 2

Richard MacCutchan · Accepted Answer · 2022-11-23T22:21:00

C++

// an array with 1 row and 0 column.
int arr[1][0] ={1};

That does not make sense, an array cannot have a dimension of zero length. And why would you want an array that contains only a single cell? You need something like:

C++

// an array with 1 row and 0 column.
int arr[2][2] ={ {1, 2}, { 3, 4} };

How do I run the program code with an array 1 row and 0 column in C++?

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