Function call missing argument list

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I have 4 classes:
Point inherits from Shape,Circle from Point and Cylinder from Circle.
point, circle, cylinder are objects to Point, Circle, Cylinder.

XML

Shape *shapeVector[3];
shapeVector[0]=&point;
shapeVector[1] = &circle;
shapeVector[2] = &cylinder;

When I do this:

C++

Shape *baseClassPtr=shapeVector[ 1 ];
baseClassPtr->GetName();

It is working.But when I do this:

C++

virtualViaPointer( shapeVector[ i ] ); // for all i(0,1,2)

   void virtualViaPointer(  Shape *baseClassPtr )    
   {                         	   
	   cout << baseClassPtr->GetName() << ": " ; 
   }

I'm getting this error:

VB

Error   2   error LNK1120: 1 unresolved externals 
Error	1	error LNK2019: unresolved external symbol "void __cdecl virtualViaPointer(class Shape const *)" (?virtualViaPointer@@YAXPBVShape@@@Z) referenced in function _wmain

Posted 19-Jan-13 23:05pm

missak boyajian

Updated 20-Jan-13 1:26am

Sandeep Mewara

v4

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SoMad · Answer 1 · 2013-01-19T23:11:00

Solution 1

Unless I am missing something, it looks like you simply have to add the parenthesis:

C++

cout << baseClassPtr->GetName() << ": " ;

You did not actually show the GetName() declaration, but to me this looks like it would fix it.

Soren Madsen

Posted 19-Jan-13 23:11pm

SoMad

Updated 19-Jan-13 23:14pm

v2

Comments

missak boyajian 20-Jan-13 5:19am

I dont know why i havent put the paranthesis. I will update the question

SoMad 20-Jan-13 5:23am

The new error message you are getting looks to me like you copy/pasted the code from your question and did not remove the <pre> tags - at least not the </pre> at the end.

Soren Madsen

missak boyajian 20-Jan-13 5:29am

I copy pasted the error from visual studio. I tried many things I dont know why its not working. GetName is a pure virtual function and i have implement it in the 3 classes except shape.

SoMad 20-Jan-13 5:37am

That is fine, but that is not the problem. Look at the error message. It is saying that your function virtualViaPointer(class Shape const *) is not declared. Look closely at the parameter, it says const. You should be able to simply modify your function to take the parameter as const.

Soren Madsen

missak boyajian 20-Jan-13 5:46am

Thanks it worked. I forgot I was using constant functions.

SoMad 20-Jan-13 5:48am

Glad I could help.

Soren Madsen