how to round the nearest ten ?

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my code is

Int64 i = ((Int64)Math.Round(Convert.ToDecimal(dr["CHARGE"]) / 10,1,MidpointRounding.AwayFromZero)) * 10;

its working but one exception is
For 100's (eg: 100,200,300 etc), if we set charge as 105,205,etc its not rounding properly. Expected result: 110,120,130 etc, but now its displaying as 100,200,300 etc.

how can avoid this error ?

this is my requirement

95 to 104.9 --> 100
105 to 114.9 --> 110

Any answer is highly appreciated. thanks in advance.

Posted 9-Jan-13 21:00pm

vasim sajad

Updated 9-Jan-13 21:13pm

v2

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kumarksj · Answer 1 · 2013-01-09T21:54:00

Solution 3

C#

if (Convert.ToDecimal(x % 10) == 5)
        {
            x = x + 1;


        }
        Int64 i = ((Int64)Math.Round(Convert.ToDecimal(x) / 10)) * 10;

Posted 9-Jan-13 21:54pm

kumarksj

*Suvabrata Roy* · Answer 2 · 2013-01-09T21:58:00

Solution 4

C#

var ii = Math.Round(Convert.ToDecimal((104.9 + 0.0000001) / 10.00)) * 10 ;

Posted 9-Jan-13 21:58pm

Suvabrata Roy

CzimerA · Answer 3 · 2013-01-09T21:59:00

Solution 5

Just add five, and round:

C#

public int round(float value)
{
   return (((int)value + 5) / 10) * 10;
}

Posted 9-Jan-13 21:59pm

CzimerA

Sandeep Mewara · Answer 4 · 2013-01-09T21:32:00

Solution 2

Try:

C#

public int RoundOff (Decimal valueToRound)
{
   return ((int)Math.Round(valueToRound / 10.0)) * 10;
}

Posted 9-Jan-13 21:32pm

Sandeep Mewara

v2

Mohd. Mukhtar · Answer 5 · 2013-01-09T21:25:00

Solution 1

Try rounding with below line.

C#

Int64 i = ((Int64)Math.Round(Convert.ToDecimal(dr["CHARGE"])/ 10,MidpointRounding.AwayFromZero)) * 10;

Posted 9-Jan-13 21:25pm

Mohd. Mukhtar