Big Oh Computation

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Good Day,

Given a pseudo code below:

<br />main()<br />{<br />for(int i=0;i<n;i++)><br />{<br />x[i]=func1(func2(x[i]));<br />}<br />}<br /><br />func1(x[])<br />{<br />for(int i=0;i<length(x);i++)><br />//Do something here<br />}<br /><br />func2(x[])<br />{<br />for(int i=0;i<length(x);i++)><br />//Do something here<br />}<br />

How can I compute for the Asymptotic notation? I know that the loop in main() is O(n) and both func1 and func2 are O(n). But How can I combine the 3? Can I even combine the 3 to get O(N^3)? or it will be just O(3N)?

Thanks! :)