Regular Expression to match a definite pattern on each occurence.

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I want to check a string against a particular occurrence that is, whenever a "/" occurs it must followed by a character or number like "/z" or "/2" or "/s".

Anyone, Please help on this as I'm new to RegEx.

I Appreciate any help.
Thanks in Advance.

Posted 12-Jun-12 23:46pm

Sunny_Kumar_

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OriginalGriff · Accepted Answer · 2012-06-12T23:53:00

Solution 1

Try:

/[sz2]

The '[' and ']' characters say "any character in this list".
Get a copy of Expresso [^] - it's free, and it examines and generates Regular expressions.

Posted 12-Jun-12 23:53pm

OriginalGriff

Comments

Sunny_Kumar_ 13-Jun-12 6:23am

Thanks a lot for this help. I'm gonna try this.

OriginalGriff 13-Jun-12 6:34am

You're welcome!

VJ Reddy 14-Jun-12 0:36am

Good suggestion. 5!

Manas Bhardwaj 15-Jun-12 3:54am

Correct +5

VJ Reddy · Accepted Answer · 2012-06-13T18:35:00

Solution 2

The Expresso program suggested by OriginalGriff is really a very good tool. It has a design mode it which the regular expression can be built interactively and it can be tested.

Alternatively, if you want to check immediately online, the http://regexhero.net/tester/[^] is a good online Regular Expression tester for testing the regular expression and it also offers help on building the regular expression.

For the case stated in the question, since any character (a to z or A to Z) or any number must follow / then I think the following regular expression

/[a-zA-Z0-9]
or
/[\w-[_]]
can be used. \w matches alpha numeric character a-z A-Z 0-9 and UnderScore. Since, under score is not required in the present case it is subtracted.

It can be tested at the above website.

Posted 13-Jun-12 18:35pm

VJ Reddy

Updated 13-Jun-12 18:36pm

v2

Comments

Sunny_Kumar_ 14-Jun-12 1:10am

Thanks a lot for the nice link. The site is really very nice and doing well as Expresso online I would say. Love this tool..thanks again :)

VJ Reddy 14-Jun-12 1:23am

You're welcome and thank you for reviewing and accepting the solution :)

Manas Bhardwaj 14-Jun-12 4:25am

Correct +5

VJ Reddy 14-Jun-12 4:36am

Thank you, Manas :)

Espen Harlinn 14-Jun-12 17:09pm

Nice answer, 5'ed!

VJ Reddy 14-Jun-12 19:52pm

Thank you, Espen :)

Manas Bhardwaj 15-Jun-12 3:54am

Good +5!

VJ Reddy 15-Jun-12 7:36am

Thank you, Manas :)