XSLT data problem

Question

0.00/5 (No votes)

See more:

Hello guys I have an xslt file I want to extract data from.

I am new to xslt but at the moment I can perform basic operations like looping through the nodes and creating element and attributes.

My problem is that I want to select a particular value from a particular node(from a list of nodes), here is an example.

<PersonsList><br />
<person><br />
<id>1233</id><br />
<name>john</name><br />
</person><br />
<person><br />
<id>444</id><br />
<name>peter</name><br />
</person><br />
<person><br />
<id>677</id><br />
<name>Amanda</name><br />
</person><br />
</PersonsList>

I want to get for example the name value say amanda if it matches the id. like in C# one would say: if (id==677) select name, Now I want the xslt equivalent.

Posted 30-May-12 23:12pm

BlaqProdukt

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Andreas Gieriet · Accepted Answer · 2012-05-31T01:13:00

The following XSLT creates an HTML table with the respective selected item marked.
The item in question can be passed as id parameter from your xslt processor - default is 677.

XML

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
  <xsl:param name="id">677</xsl:param>

  <xsl:output method="html" indent="yes"/>

    <xsl:template match="/PersonsList">
      <table border="1">
        <tr>
          <th>Id</th>
          <th>Name</th>
          <th>Selected</th>
        </tr>
        <xsl:for-each select="person">
          <xsl:sort select="id" order="ascending" data-type="number"/>
          <tr>
            <td>
              <xsl:value-of select="id"/>
            </td>
            <td>
              <xsl:value-of select="name"/>
            </td>
            <td>
              <xsl:choose>
                <xsl:when test="id=$id">yes</xsl:when>
                <xsl:otherwise>no</xsl:otherwise>
              </xsl:choose>
            </td>
          </tr>
        </xsl:for-each>
      </table>
    </xsl:template>
</xsl:stylesheet>

Output:

XML

<table border="1">
  <tr>
    <th>Id</th>
    <th>Name</th>
    <th>Selected</th>
  </tr>
  <tr>
    <td>444</td>
    <td>peter</td>
    <td>no</td>
  </tr>
  <tr>
    <td>677</td>
    <td>Amanda</td>
    <td>yes</td>
  </tr>
  <tr>
    <td>1233</td>
    <td>john</td>
    <td>no</td>
  </tr>
</table>

Id	Name	Selected
444	peter	no
677	Amanda	yes
1233	john	no

Please note that XSLT requires functional programming style, not procedural programming style. Main reason is, that you can only initialize variables, but not assign new values to variables.

Cheers
Andi

CPallini · Accepted Answer · 2012-05-30T23:46:00

Solution 1

XPath:

XML

person[id=677]/name

Posted 30-May-12 23:46pm

CPallini