Load Image Dynamically

Assuming you are using a PictureBox control to display the image, in your button click event handler you would update the Image property to the desired image.

Well, start like this, on form load or other event get all the files in given dir:

// Get files from directory (with specified extension)
string[] filePaths = Directory.GetFiles(@"c:\MyDir\", "*.bmp");

set the first item of the array in the picture box and the current item index in the page.

int currentItem = 0;
int maxItems;
...
maxItems = filePaths.Length; 

then set the image in picture box

Image image = Image.FromFile(filePaths[maxItems]);

pictureBox1.Image = image;
        pictureBox1.Height = image.Height;
        pictureBox1.Width = image.Width;

Set the next image on every click:

Image image = Image.FromFile(filePaths[maxItems]);

pictureBox1.Image = image;
        pictureBox1.Height = image.Height;
        pictureBox1.Width = image.Width;
maxItems++;

This is a rough explanation, it is on you to experiment a bit.

Cheers

protected void Button_Click(object sender, EventArgs e)
{
    this.PictureBox1.ImageLocation = getrandomfile("C:\images")
}


private string getrandomfile(string path)
        {
            ArrayList al = new ArrayList();
            DirectoryInfo di = new DirectoryInfo(path);
            FileInfo[] rgFiles = di.GetFiles("*.*");
            foreach (FileInfo fi in rgFiles)
            {
                al.Add(fi.FullName);
            }
            Random r = new Random();
            int x = r.Next(0,al.Count);

            return al[x].ToString();
        }

will actually gives random image each time.

in your page declare a variable to track which no image you are displying. here is the code

public partial class Form1 : Form
    {
        int imgNum = 0;
        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            setImage();
        }

protected void setImage()
        {
            int Maxitem=0;
            string[] filePaths = Directory.GetFiles(@"D:\MyDir\", "*.jpg");
            Maxitem=filePaths.Length;

            if (imgNum >= Maxitem) imgNum = 0;
            pictureBox1.ImageLocation = filePaths[imgNum].ToString();
            imgNum += 1;
        }
}

i give you a link here which will solve your problem.

C# Save and Load Image from Database[^]

Private MyImage As Bitmap

 Public Sub ShowMyImage(fileToDisplay As String, xSize As Integer, _
                        ySize As Integer)
     ' Sets up an image object to be displayed.
     If (MyImage IsNot Nothing) Then
         MyImage.Dispose()
     End If

     ' Stretches the image to fit the pictureBox. 
     pictureBox1.SizeMode = PictureBoxSizeMode.StretchImage
     MyImage = New Bitmap(fileToDisplay)
     pictureBox1.ClientSize = New Size(xSize, ySize)
     pictureBox1.Image = CType(MyImage, Image)
 End Sub