Overload a function, all double

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Hi All,

I have a bit of an odd request, I'd like to overload a function. Yes, yes, you all will think but that is easy. But I don't want to overload it in the conventional way of feeding two values to the function and the overloading is done by having the values as double or integer or whatever the case might be...

I need the following:

VB

public function circle (byval diameter as double, byval radius as double, byval area as double, byval cirumference as double) as double

'Depending on which byval I fill in, and which one I indicate with say a "0", the 0 unknown is returned

end function

Posted 6-Feb-12 20:15pm

JacquesGrobler

Updated 6-Feb-12 20:28pm

Sergey Alexandrovich Kryukov

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Sergey Alexandrovich Kryukov 7-Feb-12 2:28am

Corrected tags. VB.NET is not VB. Tags are important.
--SA

Sergey Alexandrovich Kryukov 7-Feb-12 2:30am

What do you call "overload". Or, in other words, where is your second function?
--SA

JacquesGrobler 7-Feb-12 2:38am

Do I have to have more than one function to overload?

And if so, what do I then call what I am trying to do?

Sergey Alexandrovich Kryukov 7-Feb-12 2:44am

Always. Otherwise if is not called "overloading". Bad term, confusing. We don't have to use it to explain the syntax and semantic.

I explained everything you may need in my answer, please see.
--SA

JacquesGrobler 7-Feb-12 6:32am

Anybody able to assist me please?

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Sergey Alexandrovich Kryukov · Answer 1 · 2012-02-06T20:43:00

Maybe you don't know what is overloading. No wonder, the term is quite confusing, because nothing is actually "loaded", so what could be "overloaded"? Actually, nothing.

It really means that two or more methods have the same name (in the same class or structure, that is, the same fully-qualified name), but different signatures, and each particular signature could be recognized be the compiler by the call. That said, depending on the particular call parameters in the code of the actual call, such recognition may or may not be possible, and the ambiguity will cause compilation error.

Additionally, you should understand that VB.NET is still a language with strong typing, despite of implicit conversion typical for this language. Please see http://en.wikipedia.org/wiki/Strong_typing[^].

That said: if your idea is a dynamic parameter, it's a wrong idea. If you formal parameter is double, it will always be double, even if the actual parameter is int — it is merely converted to double, so, from the standpoint of the method implementation, it is always double and nothing else.

Actually, your question is not clear and/or incorrectly formulated and/or makes no sense. Not to worry — I hope my explanations are enough for you to sort things out.

—SA

Kschuler · Answer 2 · 2012-02-07T05:34:00

Want you want to do is possible, but in my opinion you are making it harder than it needs to be. Instead of making a function, why not make a simple method? Pass your variables in ByRef (By Reference) so you can update them directly:

VB

Public Sub circle(ByRef diameter As Double, ByRef radius As Double, ByRef area As Double, ByRef cirumference As Double)

If diameter <> 0 Then
   'Calculate all parameters other than diameter
End If 

If radius <> 0 Then
   'Calculate all parameters other than radius
End If

'And so on...

End Sub

This way, when call the method, you already have all the variables setup to retrieve the proper values.

VB

Dim diameter as Double = 10
Dim radius as Double = 0
Dim area as Double = 0
Dim circumference as Double = 0
circle(diameter, radius, area, circumference)
'Now you already know which "return" value is for which variable

SteveAdey · Answer 3 · 2012-02-07T05:47:00

Something like this is what I guess you want:

public static double Circle(double? diameter = null, double? radius = null, double? area = null, double? circumference = null)
{
    double result = 0.0;

    if (diameter.HasValue)
    {
        // Do Something
    }

    if (radius.HasValue)
    {
        // Do Something
    }

    if (area.HasValue)
    {
        // Do Something
    }

    if (circumference.HasValue)
    {
        // Do Something
    }

    return result;
}

You can then call this with named parameters:

Circle(radius: 10.0);

Sorry it's in C#, but that's what I know.

Overload a function, all double

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