making control visible in gridview asp.net page

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Hi,

i have a control in gridview which i have made visible=false in design,i have added that control in item template. and in grdview_RowEditing event i want to make that control visible true,

C#

protected void grdview_RowEditing(object sender, grdviewEventArgs e)
        {
            try
            {
                if(text!="")
                {
                    ImageButton imgbtnexm5 =(ImageButton)grdview.Rows[e.NewEditIndex].FindControl("imgbtnexm5");
                    imgbtnexm5.Visible = true;
                }
}
}

but that control is not visible,
Note:i have added the control in item template,and trying to make the visibility true in edit event,and also i tried adding it in edit template but i wont find the control at all.may be because the row is not yet edited.

Q:how do i make the control visible in RowEditing event,and which template should i add the control.

C#

<itemtemplate>
                                        <asp:Label ID="lblDate" runat="server" Text='<%# Bind("Date") %>'>
                                        <asp:ImageButton ID="imgbtnexm5" runat="server" ImageUrl="~/images/myimage.gif" Visible="false"/>
                                    </itemtemplate>

thanks in advance.

Posted 10-Nov-11 17:42pm

girish sp

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shek124 · Accepted Answer · 2011-11-10T17:47:00

Hi,

Better You would have the control in Edit template, that would be visible automatically in edit status .

XML

<asp:TemplateField HeaderText="Name" SortExpression="FirstName">
            <EditItemTemplate>
                <asp:TextBox ID="TextBox1" runat="server"
                    Text='<%# Bind("FirstName") %>'></asp:TextBox>
            </EditItemTemplate>
            <ItemTemplate>
                <asp:Label ID="Label1" runat="server"
                    Text='<%# Bind("FirstName") %>'></asp:Label>
                <asp:Label ID="Label2" runat="server"
                    Text='<%# Eval("LastName") %>'></asp:Label>
            </ItemTemplate>
        </asp:TemplateField>

girish sp · Accepted Answer · 2011-11-10T23:13:00

Solution 2

hi ,
i pasted my code in other system n it worked,

thanks anyways

Posted 10-Nov-11 23:13pm

girish sp

Updated 10-Nov-11 23:14pm

v2

Comments

RaviRanjanKr 11-Nov-11 5:16am

You should post as a Comment by using Have a Question or Comment Instead of posting as an Answer :)