how to use JavaScript to call a php function and pass an argument

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I need a Javascript to call a PHP function , like that :
The problem i encounter is that the parameter id does not get passed .
Function MODIFICA($num) is defined in the same php file , and returns data using "print" ( this part works)

HTML

<p id="php_code"> Nothing yet.</p>

Java

function JSModify(id)
 {
document.getElementById("php_code").innerHTML="<?php MODIFICA("" + id + "");/???>";
return;
 }

PROBLEM :

Posted 17-Sep-11 4:29am

Radu Slavila

Updated 17-Sep-11 4:39am

v5

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Solution 2

oh , so that's why i always get the function MODIFICA(0) instead of my id ... tnx for help .

Posted 17-Sep-11 4:59am

Radu Slavila

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Graham Breach · Accepted Answer · 2011-09-17T04:58:00

You can't call PHP directly using Javascript. Javascript happens in the browser and PHP happens on the server, so by the time the Javascript is called the page has already been served.

If you really need to call PHP functions from Javascript you can use AJAX to make another request to the server.