Adding and inserting values of same ID in sql table

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Hi,
I am having trouble writing a query that accurately does what I need.
I have a table like the following

Id    Date        Value     Cumulative
1     Jan 1st       0.2
2     Jan 1st       0.5
1     Jan 2nd       0.7
2     Jan 2nd       0.6
4     Jan 2nd       0.1
1     Jan 3rd       0.02
3     jan 3rd      0.01
4     Jan 3rd      0.03

I want to write a query which inserts the cumulative column with the sum of the value for the same Ids i.e.,

Id     Cumulative
1        0.2
2        0.5
1        0.9  (0.2+0.7)
2        1.1  (0.5+0.6)
4        0.1
1        0.92  (0.2+0.7+0.02)
3        0.01
4        0.13  (0.1 + 0.03)

Thanks in advance.

Posted 28-Aug-11 15:48pm

Ananth Ramchandran

Updated 28-Aug-11 18:52pm

Prerak Patel

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Prerak Patel 29-Aug-11 0:54am

If you are having table like this, you need to consider the redesign.

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kennytan_ph · Answer 1 · 2011-08-28T22:06:00

It would be easy if you have an additional sequence column (e.g. UniqeID). If you have, you can just have it this way

SQL

Update CumulativeTable
    SET Cumulative = Value + (Select Sum(Value) From CumulativeTable Where UniqueID < c.UniqueID
                        AND ID = c.ID)
From CumulativeTable c

or if you don't have, you can try this,

SQL

DECLARE @TempTable TABLE (UniqueID int IDENTITY,
ID int,
Value numeric(18,3),
Cumulative numeric(18,3)
)

DECLARE @TempTable TABLE (UniqueID int IDENTITY,
ID int,
Value numeric(18,3),
Cumulative numeric(18,3)
)

Insert Into @TempTable (ID, Value, Cumulative)
Select ID, Value, Cumulative From CumulativeTable

Update CumulativeTable
	SET Cumulative = COALESCE(c.Value + (Select Sum(Value) From @TempTable Where UniqueID < c.UniqueID
						AND ID = c.ID),0)
From CumulativeTable t, @TempTable c
Where t.ID = c.ID AND t.Value = c.Value

but this will not give you correct value if you have multiple records with the same ID and value