onkeyReleased event in swing

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hi everyone.

i have a problem pertaining to text box that do not accept any characters.
Here is the situation, i have a text box that do not accept any characters, i have an onkeyReleased event that whenever i press any key in keyboard, it says, "Ooops..,this text box do not accept any characters!". How can i do that?

Please help me.

Posted 26-Apr-11 14:23pm

Guts_ryo

Updated 26-Apr-11 14:26pm

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santosh dhanawade · Answer 1 · 2011-04-26T23:14:00

Your class should implement keyListener adapter to do so,

public class KeyListenerTester extends Frame implements KeyListener

Then implement,

public void keyReleased(KeyEvent Event) {
   int key=evt.getKeyCode();  ///using validation here
                              /// ascii code A=65 ,Z=90 ,a=97 ,z=122 
   if((key>=65&&key<=90)||(key>=97&&key<=122))
   { 
       ///making Textbox empty
       JOptionPane.showMessageDialog(frame,"Ooops..,this text box do not accept any characters!.");
   }

Try it,
its just suggestion then reply

Sergey Alexandrovich Kryukov · Answer 2 · 2011-04-26T15:01:00

Showing this is easy, but I feel you need the code to behave accordingly, to prevent characters from entering.
This is a bit less than trivial. You will need to use onKeyPress instead.

See:

JavaScript

<html>
   <head>
      <script type="text/javascript"><!--
         function filterOut(eventInstance) {
            var character = String.fromCharCode(eventInstance.which);
            if (eventInstance.which == 8)
               character = "backspace";
            alert("You want to enter " + character +
               ", Guts_ryo? Relax, this text box do not accept any characters!"); 
            eventInstance.preventDefault();
            eventInstance.returnValue = false;
            return false;
         } //filterOut
      --></script>
   </head>
<body">

<input type="text" onkeypress="filterOut(event)"/>

</body>
</html>

Pay attention for special processing of backspace. You can use this code to filter out some character sets to get, say, digits only or something like that. Don't forget to allow backspace in all cases.

Sorry, I misread it; though it was "Javascript"! Oops! :-)

—SA

TorstenH. · Answer 3 · 2011-04-26T22:49:00

- add a KeyListener to the Component you're entering the text in.
- The KeyListener has to implement KeyListener and therefor the method: public void keyReleased(KeyEvent oEvent) {/* doany(); */}
- the KeyEvent provides the source of the event and therefor the entered text.
- update your textbox with the won data.

public void keyReleased(KeyEvent oEvent) {
    Control oControl = (Control)oEvent.getSource();
        final Text oText = (Text) oEvent.widget;
        if ((oText.getText() == null) || oText.getText().equals("")) {
            // setDefaultText (like "")
        } else {
            // use String from oText.getText()
        }
}

regards
Torsten

onkeyReleased event in swing

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Solution 4

Solution 1

Sorry, I misread it; though it was "Javascript"! Oops! :-)

Solution 3

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