TextBox (if then)

Question

2.00/5 (1 vote)

See more:

txtyear1 is a textbox that has the value of 2010
txtyear2 is a textbox that has the value of 2011

if (txtyear2.Text >= txtyear1.Text)

how do you make the condition above to work?

Posted 19-Dec-10 20:06pm

wolfsor

Updated 19-Dec-10 20:14pm

Toniyo Jackson

v5

Add a Solution

Comments

Toniyo Jackson 20-Dec-10 2:12am

What you want to check? length or value?

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

**JF2015** · Accepted Answer · 2010-12-19T20:15:00

Solution 3

One example:

C#

if (Int16.Parse(txtyear2.Text) >= Int16.Parse(txtyear1.Text))
{
}

you should also check out Int16.TryParse or Convert.ToInt16

Posted 19-Dec-10 20:15pm

JF2015

v2

Comments

TweakBird 20-Dec-10 2:26am

Good One

Vigneshb6 20-Dec-10 2:29am

nice

wolfsor 20-Dec-10 2:43am

what's the difference between Int16 and Int32?

JF2015 20-Dec-10 3:15am

The difference is the value range.
Int 16 -- (-32768 to +32787)
Int 32 -- (-2,147,483684 to +2,147,483683)
Int 64 -- (-9223372036854775808 to +9223372036854775807)

So, for normal years, int16 should be enough.

Anton Levshunov 20-Dec-10 4:16am

My small remark about possible exception when string parse.

Toniyo Jackson · Accepted Answer · 2010-12-19T20:13:00

Solution 1

Try this,

if (Convert.ToInt32(txtyear2.Text) >= Convert.ToInt32(txtyear1.Text))
{
}

Posted 19-Dec-10 20:13pm

Toniyo Jackson

Updated 19-Dec-10 20:28pm

v2

Jaffar Ramnad · Accepted Answer · 2010-12-19T20:14:00

Solution 2

try this

if (Convert.ToInt32(txtyear2.Text) >= Convert.ToInt32(txtyear1.Text))

Posted 19-Dec-10 20:14pm

Jaffar Ramnad