Open file using openfiledialog

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I am using openfiledialog in C# for opening a .csv file. Now I want to filter .csv files which starts with letter 'L'.
eg. If I open dialog box using opendialog with .csv filter, it shows me all .csv files in current folder. But I want to filter the .csv files which has name starts with letter 'L'.
Is it possible?

What I have tried:

C#

private void btmImport_Click(object sender, EventArgs e)
       {
           try
           {
               string filename = "";
               OpenFileDialog dialog = new OpenFileDialog();
               dialog.Title = "Open CSV File";
               dialog.Filter = "CSV Files (*.csv)|*.csv";
               if (dialog.ShowDialog() == DialogResult.OK)
               {
                   filename = dialog.FileName;
               }
               else
               {
                   return;
               }
               //code to load file in datatable.
               DataTable data = new DataTable();
               data = NewDataTable(filename, ",", true);
               grdDataImp.DataSource = data;
           }
           catch (Exception)
           {
               throw;
           }

       }

Posted 3-Apr-18 4:46am

webmail123

Updated 3-Apr-18 5:18am

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Comments

Richard MacCutchan 3-Apr-18 11:08am

You need to add the letter to the beginning of the "*.csv" filter.

2 solutions

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Christiaan van Bergen · Accepted Answer · 2018-04-03T05:16:00

Solution 1

Change your filter to

C#

dialog.Filter = "CSV Files (L*.csv)|L*.csv";

Posted 3-Apr-18 5:16am

Christiaan van Bergen

OriginalGriff · Accepted Answer · 2018-04-03T05:20:00

Try:

private void btmImport_Click(object sender, EventArgs e)
    {
    string filename = "";
    OpenFileDialog dialog = new OpenFileDialog();
    dialog.Title = "Open CSV File";
    dialog.Filter = "CSV Files (L*.csv)|L*.csv";
    if (dialog.ShowDialog() == DialogResult.OK)
        {
        filename = dialog.FileName;
        //code to load file in datatable.
        DataTable data = new DataTable();
        data = NewDataTable(filename, ",", true);
        grdDataImp.DataSource = data;
        }
    }

Catching all exceptions just to rethrow them isn't really needed...