Python convert string and variable to list name

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i have the following code (this sudo code that reflect the real values in my code)

i have alist :

Python

virt_who_attached_to_std_vdc = ['A', 'B' , 'c' ]

i want to check if an item in that list ,but i want check the list name as the below variable:

Python

vdc_sub = 'std'
	sub = 'virt_who_attached_to_'+vdc_sub+'_vdc'

if i am printing the value of "sub" i am getting the same name as the original list ,but this is a string of course:

print(sub)
virt_who_attached_to_std_vdc

so if i will check if 'a' is in sub like this :

Python

if 'A' in sub:

its doesnt print anything ,how do i represent the sub variable as the original virt_who_attached_to_std_vdc list?

What I have tried:

tried to convert sub it to list

Python

sublist = list(sub)
sublist
['v', 'i', 'r', 't', '_', 'w', 'h', 'o', '_', 'a', 't', 't', 'a', 'c', 'h', 'e', 'd', '_', 't', 'o', '_', 's', 't', 'd', '_', 'v', 'd', 'c']

Posted 26-Dec-17 3:46am

max_il

Updated 26-Dec-17 6:06am

Richard MacCutchan

v2

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Thomas Daniels · Answer 1 · 2017-12-26T07:48:00

If I understand correctly, you want to get the list that has the name stored in sub and check if 'A' is in that list.

First you need to know: is the list a global variable, or a local variable?

If it is a global variable, you can do this:

Python

if 'A' in globals()[sub]:
    # code

globals() returns all global variables as a dict, so you can get your list with the [sub] syntax.

If the list is a local variable, you have to use locals() instead of globals():

Python

if 'A' in locals()[sub]:
    # code