How to create a pivot query in SQL server without aggregate function

Question

0.00/5 (No votes)

See more:

I am using MS SQL SERVER and I have following data:

ValDate Month CurID SpotRate_Cad
11/1/2016 11 cad 1.00000000
11/1/2016 11 usd 1.30000000
11/1/2016 11 eur 1.51000000
11/2/2016 11 cad 1.00000000
11/2/2016 11 usd 1.31000000
11/2/2016 11 eur 1.50000000

I would like to have this format

Date Month cad usd eur
11/1/2016 11 1.00000000 1.30000000 1.51000000
11/1/2016 11 1.00000000 1.31000000 1.50000000

What I have tried:

SELECT *
FROM (
SELECT npv.ValDate, month(npv.ValDate) as Month, rtrim(npv.CurID) as CurID, (npv.SpotRate) as SpotRate_Cad

FROM boss_bo.dbo.NPVPLFxRate as npv
LEFT JOIN boss_bo.dbo.NPVPLFxRate as npv2
ON (npv.ValDate =npv2.ValDate)

WHERE (npv.ValDate<='2017-06-20')
AND (npv.ValDate>='2016-11-01')
AND (npv2.CurID = "usd")
) fx

PIVOT (
ValDate, Month, SpotRate
FOR CurID IN
([cad], [usd], [eur])
) AS PVT

Posted 25-Jun-17 12:23pm

Member 13278062

Updated 26-Jun-17 0:23am

Add a Solution

Comments

Andy Lanng 26-Jun-17 3:21am

Don't use pivot. What you want is not a function of pivot.

Kornfeld Eliyahu Peter 26-Jun-17 4:29am

Do you always have a fixed number of currencies to merge?

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

FranzBe · Answer 1 · 2017-06-26T00:23:00

CREATE TABLE #thetable 
( id            INT IDENTITY(1,1) NOT NULL ,
ValDate         DateTime,
[Month]         INT,
CurID           CHAR(3),
SpotRate        FLOAT
)

INSERT INTO #thetable (ValDate, [Month], CurID, SpotRate) VALUES ('11/1/2016',11, 'cad', 1.0)
INSERT INTO #thetable (ValDate, [Month], CurID, SpotRate) VALUES ('11/1/2016',11, 'usd', 1.3)
INSERT INTO #thetable (ValDate, [Month], CurID, SpotRate) VALUES ('11/1/2016',11, 'eur', 1.51)
INSERT INTO #thetable (ValDate, [Month], CurID, SpotRate) VALUES ('11/2/2016',11, 'cad', 1.0)
INSERT INTO #thetable (ValDate, [Month], CurID, SpotRate) VALUES ('11/2/2016',11, 'usd', 1.31)
INSERT INTO #thetable (ValDate, [Month], CurID, SpotRate) VALUES ('11/2/2016',11, 'eur', 1.5)


SELECT * FROM #thetable

SELECT
   dateadd(day,datediff(day,0, t.ValDate ),0) as DATE
   ,[Month]
   ,SUM(cad) as cad
   ,SUM(usd) as usd
   ,SUM(eur) as eur
FROM
(
SELECT
  ValDate
  ,[Month]
  ,CASE WHEN CurID = 'cad' THEN SpotRate END AS 'cad'
  ,CASE WHEN CurID = 'usd' THEN SpotRate END AS 'usd'
  ,CASE WHEN CurID = 'eur' THEN SpotRate END AS 'eur'
FROM  #thetable
) t
GROUP BY 
dateadd(day,datediff(day,0, t.ValDate ),0)
,[Month]