Please identify what this is intended to do

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58..62 | % { nslookup 192.168.1."$_"}

I'm confused as to what the two successive periods represent. I understand the pipe and nslookup command but not the rest.

Thanks.

What I have tried:

58..62 | % { nslookup 192.168.1."$_"}

I'm confused as to what the two successive periods represent. I understand the pipe and nslookup command but not the rest.

Thanks.

Posted 22-Feb-17 3:34am

Member 13017232

Updated 22-Feb-17 9:24am

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Graeme_Grant 22-Feb-17 9:48am

I don't program in Bash but it looks like a range to me...

Richard MacCutchan 22-Feb-17 10:13am

What happens when you run it?

[no name] 22-Feb-17 10:51am

Why are you writing code you don't understand?

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Albert Holguin · Answer 1 · 2017-02-22T08:28:00

So, that doesn't appear to be valid bash code, starting a line with "58..62" is invalid, as it's not a command or shortcut... but if it's pseudo-code I'd guess it's attempting to run nslookup on a range of IP addresses.

This gets you the same thing that your code appears to be attempting to do:

Bash

#!/bin/bash
for i in {58..62}; do nslookup 192.168.1.$i ; done

Patrice T · Answer 2 · 2017-02-22T09:24:00

Quote:
58..62

A simple search in bash reference manual gives the answer.
Since we are not a free search service, you will to find the answer by yourself/
1) find Bash reference Manual
2) search ".."

Advice: If you want to avoid rude answers in future, do at least basic researches before asking questions here.

Please identify what this is intended to do

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