how to get contain start with [ and end with ] only from string

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how to get contain start with [ and end with ] only from string

[ANC 2 DATE] = [yes] AND [AllIFADone] = [YES] AND

i want out out in array

like
[ANC 2 DATE]
[yes]
[AllIFADone]

other should get ignore

Posted 7-Dec-15 20:48pm

Member-515487

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3 solutions

Solution 2

Member-515487's solution will work, but the use of Balancing Groups is a better idea:

(?<sb>\[).*?(?<-sb>\])

Posted 7-Dec-15 21:01pm

OriginalGriff

Solution 3

This can be done without using RegEx:

C#

char[] splitChars = new[] { '[' };

string anc = @"[ANC 2 DATE] = [yes] AND [AllIFADone] = [YES] AND";

string[] ancSplit = anc.Split(splitChars, StringSplitOptions.RemoveEmptyEntries)
    .Select(strx => ('[' + strx.Substring(0, strx.IndexOf(']') + 1))).ToArray();

However, I am not claiming that doing it this way is better than using a RegEx.

Sample result:

C#

? ancSplit
{string[4]}
    [0]: "[ANC 2 DATE]"
    [1]: "[yes]"
    [2]: "[AllIFADone]"
    [3]: "[YES]"

Posted 7-Dec-15 22:55pm

BillWoodruff

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Member-515487 · Accepted Answer · 2015-12-07T20:55:00

Solution 1

C#

string str = "[ANC 2 DATE] = [yes] AND [AllIFADone] = [YES] AND ";
           var pattern = @"(\[(?:.*?)\])";

           MatchCollection mcol = Regex.Matches(str, pattern);

           foreach (Match m in mcol)
           {
               Console.WriteLine(m);
           }

Posted 7-Dec-15 20:55pm

Member-515487