Call two web service methods simultaneously(parallel)

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Hello All.......

I am new in .Net development..........

I want to call two web service methods simultaneously(parallel) using c# code from the application, web service is built as a separate application. In my application, one web service method should get called & it is not needed to wait for the response, then another service method should get called & it is not needed to wait for the response, but after calling both of these service methods, I need to wait for the respond for first method & as per the result I need to proceed ahead, what is the best way to perform this?

Thanks in advance.

Regards

Posted 6-Aug-15 0:06am

Member 3153152

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RAJKUMAR M G 7-Aug-15 6:25am

Try to tell clearly...

2 solutions

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kellyapt1 · Answer 1 · 2015-08-07T08:14:00

The simplest solution would be to use the HttpClient class then make async calls and wait for those tasks to complete. See sample below.

C#

static void Run()
{
    //Follow steps at this link for addding a reference to the necessary .NET library:
    //http://stackoverflow.com/questions/9611316/system-net-http-missing-from-    
    //namespace-using-net-4-5

    //Create an HTTP Client
    var client = new HttpClient();

    //Call first service
    var task1 = client.GetAsync("http://www.cnn.com");

    //Call second service
    var task2 = client.GetAsync("http://www.google.com");

    //Create list of all returned async tasks
    var allTasks = new List<Task<HttpResponseMessage>> { task1, task2 };

    //Wait for all calls to return before proceeding
    Task.WaitAll(allTasks.ToArray());

}

kellyapt1 · Answer 2 · 2015-08-07T11:50:00

Solution 2

Good recommendations (especially around the params). With the "try to tell it clearly...", I thought that keeping it simple in terms of not returning another task would make things simpler to understand.

If I were to return a Task from this method I would make it generic and return an array of HttpResponseMessages:

XML

static Task<HttpResponseMessage[]> Run()
{
    ...
    return Task.WhenAll(task1, task2);
}

Posted 7-Aug-15 11:50am

kellyapt1

Comments

Matt T Heffron 7-Aug-15 18:17pm

This really should have been a reply to Richard's comments on your other Solution.
He'll not see this unless he happens to return to this question.
As a reply, he'd have gotten an email notification.
Posting this another Solution looks like abuse of the reputation points system.

kellyapt1 7-Aug-15 18:25pm

Fair enough. Did not know that I can reply directly like that - first time really doing anything in this forum. Lesson learned. Thanks.