How to count numbers

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I've made a code for calculating odd and even number from 1 to X integer and my program showing the result. But I need to add one thing in my code that how to calculate how many odd/even numbers are in the list.

As Example:Sample Output

1 2 3 4 5 6 7 8 9 10
The Even number are: 2
The Even number are: 4
The Even number are: 6
The Even number are: 8
The Even number are: 10
There are 5 even numbers <- need to add it in my code

The odd number are: 1
The odd number are: 3
The odd number are: 5
The odd number are: 7
The odd number are: 9
There are 5 odd numbers

What I have tried:

C++

/*My trying code is below:*/

#include <stdio.h>

int main() 
{
  int i, j; 
  int X=10;

  for(i=1;i<=X;i++)
  {
  printf("%d\t", i);
  }
  printf("\n");
 for(i=1;i<=X;i++)
 {
    if((i%2)==0)
 {
  printf(" The Even number are: %d\n", i);
 }
    
}

 printf("\n");
 
 for(i=1;i<=X;i++)
  {
  if((i%2)!=0)
  {
  printf(" The odd number are: %d\n", i);
    }
     }
  return 0;
}

Posted 19-Aug-18 1:39am

Member 13954054

Updated 19-Aug-18 1:54am

Patrice T

v2

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Comments

OriginalGriff 19-Aug-18 7:50am

And?
What does it do that you didn't expect, or not do that you did?
Are there any error messages? If so, where, and what?
Where are you stuck?
What help do you need?

Richard MacCutchan 20-Aug-18 4:41am

Add a counter (or two counters) to your program, and add 1 to them for each number you find.

Member 13954054 20-Aug-18 4:48am

Dear Richard,
Thanks for your reply. But I can't code to make a counters in my code. Could you please help me? In my code you see that I use two loops if and for. By using these 2 loops i want see how many odd and even numbers in list.

As example in output:
1 2 3 4 5 6
Even: 2 4 6
total even: 3
odd: 1 3 5
total odd: 3

Regards
Manash

Richard MacCutchan 20-Aug-18 5:03am

Seriously? You cannot create a variable, initialise it to zero and add 1 to it each time you find an even number? I suggest you go back and study your course notes.

Member 13954054 20-Aug-18 5:36am

Dear,
See my code below but I fail again. I couldn't understand where should I intial the variable that means in if loop or others?

#include <stdio.h>

int main()
{
int i, j;
int X=10;
printf(" The numbers are: \n");
for(i=1;i<=X;i++)
{
printf("%d\t", i);
}
printf("\n\n");
printf(" The Even number are:");
for(i=1;i<=X;i++)
{
if((i%2)==0)
{
printf(" %d ", i);
int j=0;
j=j+1;
printf("%d", j);
}

}

printf("\n\n");
printf(" The odd number are: ");
for(i=1;i<=X;i++)
{
if((i%2)!=0)
{
printf(" %d ", i);
}
}
return 0;
}

output:

The numbers are:
1 2 3 4 5 6 7 8 9 10

The Even number are: 2 1 4 1 6 1 8 1 10 1

The odd number are: 1 3 5 7 9

Richard MacCutchan 20-Aug-18 5:40am

Try using meaningful variable names and it will help you enormously. So create two variables: oddCount and evenCount. Initialise each one to zero at the obvious place. Then whenever you find an odd number add 1 to oddCount, whenever you find an even number add 1 to evenCount.

Member 13954054 20-Aug-18 6:53am

Hellooooo Richard,
Many Many Many Many thanks dear !!!!
I've solved it my problem what I want. Please see below code and and output:

#include <stdio.h>

int main()
{
int i, j;
int X=10;
int even=0;
int odd=0;

printf(" The numbers are: \n");
for(i=1;i<=X;i++)
{
printf("%d\t", i);
}
printf("\n\n");
printf("The Even number are:");
for(i=1;i<=X;i++)
{
if((i%2)==0)
{
printf(" %d ", i);
even=even+1;

}
}
printf("\nThe total even number is: %d", even);

printf("\n\n");

printf("The odd number are: ");
for(i=1;i<=X;i++)
{
if((i%2)!=0)
{
printf(" %d ", i);
odd=odd+1;
}
}
printf("\nThe total odd number is: %d", odd);
return 0;
}

Output:
The numbers are:
1 2 3 4 5 6 7 8 9 10

The Even number are: 2 4 6 8 10
The total even number is: 5

The odd number are: 1 3 5 7 9
The total odd number is: 5

Appreciate for your cordial help for me.. Thanks again...

Best Regards
Manash

Richard MacCutchan 20-Aug-18 7:02am

Happy to help.

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Patrice T · Answer 1 · 2018-08-19T01:54:00

Quote:
But I need to add one thing in my code that how to calculate how many odd/even numbers are in the list.

How can you write correct code to list odd and even numbers and be unable to count them?

Learn to indent properly your code, it show its structure and it helps reading and understanding. It also helps spotting structures mistakes.

C++

/*My trying code is below:*/

#include <stdio.h>

int main()
{
  int i, j;
  int X=10;

  for(i=1;i<=X;i++)
  {
    printf("%d\t", i);
  }
  printf("\n");
  for(i=1;i<=X;i++)
  {
    if((i%2)==0)
    {
      printf(" The Even number are: %d\n", i);
    }

  }

  printf("\n");

  for(i=1;i<=X;i++)
  {
    if((i%2)!=0)
    {
      printf(" The odd number are: %d\n", i);
    }
  }
  return 0;
}

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