Regex to accept exactly 11 digit start from 07 or can accept letter "NONE"

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I have to write a regular expression which will accept 11 digit strat from 07 (LIKE 07123456789) or can accept NONE, and I am storing this regex in my DB

What I have tried:

(^[Nn][Oo][Nn][Ee]$)|^07\d{9}$

Posted 11-May-18 1:59am

kumarravishankar

Updated 12-May-18 0:26am

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GKP1992 11-May-18 8:09am

What is the problem with the one you came up with? The only thing I see is that your regex can accept "None" irrespective of the case of the letters. If you want only "NONE" specify it literally.

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OriginalGriff · Answer 1 · 2018-05-11T02:10:00

Solution 1

Try:

^(NONE)|(07\d{9})$

If you want to use regular expressions, get a copy of Expresso[^] - it's free, and it examines and generates Regexes.

Posted 11-May-18 2:10am

OriginalGriff

Updated 11-May-18 2:14am

v2

Patrice T · Answer 2 · 2018-05-11T02:12:00

What is the problem with this RegEx ?
The RegEx is matching 'none' and '07345678901'
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Just a few interesting links to help building and debugging RegEx.
Here is a link to RegEx documentation:
perlre - perldoc.perl.org[^]
Here is links to tools to help build RegEx and debug them:
.NET Regex Tester - Regex Storm[^]
Expresso Regular Expression Tool[^]
RegExr: Learn, Build, & Test RegEx[^]
This one show you the RegEx as a nice graph which is really helpful to understand what is doing a RegEx:
Debuggex: Online visual regex tester. JavaScript, Python, and PCRE.[^]

Sikdar Ranjan · Answer 3 · 2018-05-12T00:28:00

Solution 3

Plz Use

^(NONE)|(07\d{9})$

Posted 12-May-18 0:28am

Sikdar Ranjan